125 over 1000 in Simplest Form means in its simple fraction form.
Now, to get the simplest form of 125/1000, find the HCF or GCD of both numerator and denominator i.e, 125 and 1000.
HCF of 125, 1000 = 125
Then, divide both numerator and denominator by 125
i.e,
Hence, is the simplest form of 125 over 1000.
Let the speed of the boat in still water is 'w'
Speed of the current is 'c'
Let the distance between two places is 'd'
According to the question, motorboat takes half time to cover a certain distance downstream than upstream.
=> 2w - 2c = w + c
=> w = 3c
=> c : w = 1 : 3
Hence, the ratio between rate of current(c) and rate of boat in still water(w) = 1 : 3
Let the original avg expenditure be x
Total expenditure = 35x
?35x + 42 = (x-1) X 42
?35x + 42 = 42x ?42
?7x = 84
?x = 12
So, initial expenditure = 12 X 35 = 420
Speed of the current = 24-16/2
= 8/2
= 4 km/hr.
From March 6th to November 11th,
there are 250 days and
Thus 250 x 24 hours
So from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.
Given = (0.2 * 0.2 + 0.01) / ( 0.1 * 0.1 + 0.02) = (0.04 + 0.01) / (0.01 + 0.02) = 0.05 / 0.03 = 5/3...
speed = 12 km/h =
distance covered =
time taken = distance /speed =
Ratio of length and breadth is 6 : 5
? Length = 6x
Breadth = 5x
? Area = l x b = 30x2
? Perimeter = 2 (l + b) = 2(6x + 5x) =22x
? (30*x*x)/(22x)= 60/11
? X = 4
? Length = 6x = 6 x 4 = 24 units
Let the speed of current = 'C' km/hr
Given the speed of boat in still water = 6 kmph
Let 'd' kms be the distance it covers.
According to the given data,
Boat takes thrice as much time in going the same distance against the current than going with the current
i.e,
Hence, the speed of the current C = 4 kmph.
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