=
It is in the form of
= 2(40000 + 289) = 80578.
Let, Hema attempted 'k' sum correctly, then
k x 3 -2 x(35-k) = 60
5k = 130
k = 26
so 26 correct sums.
Given that ,
=> x-y=3, x+y=5
=> x = 4
a+b=5 ...(1) and 3a+2b=20 ...(2)
Multiplying (1) by 2 and subtracting from (2), we get : a=10.
Putting a=10 in (1), we get : b=-5
Therefore, (3a+b) = 3 x 10+(-5)=30-5=25.
The given equation is in Mixed fraction.
Now to solve this type of fractions,
Let the price of each note book be Rs.x.
Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.
Hence xy = 300
=> y = 300/x
(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy
=>5(300/x) - 10x - 50 = 0 =>
multiplying both sides by -1/10x
=>
=> x(x + 15) - 10(x + 15) = 0
=> x = 10 or -15
As x>0, x = 10.
The given 3b - 7 < 32 can be solved as
3b - 7 < 32
3b < 39
b < 13.
given
=>
Now squaring on both sides
=>
=> 100 x ? = 1600
=> ? = 16
If number of visitors on 1st, 2nd, 3rd, 4th & 5th day are k, l, m, n & o respectively, then
k + l + m + n = 58 x 4 = 232 ---- (i) &
l + m + n + o = 60 x 4 = 240 ---- (ii)
Subtracting (i) from (ii), we get
o-k = 8 ---(iii)
Given, k/o = 8/9 ----(iv)
So from (iii) & (iv), we get
a = 64, e = 72
Therefore, number of visitors on 5th day is 72.
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