P = 68000, R = % & T = 9 months (3/4 years)
Let the sum be Rs. x.
I gives, S.I. = Rs. 7000 and T = 7 years.
II gives, Sum + S.I. for 5 years = 2 x Sum Sum = S.I. for 5 years.
Now, S.I. for 7 years = Rs. 7000.
therefore, S.I. for 1 year = Rs. 1000.
Thus, I and II both are needed to get the answer.
1. To find the interest, subtract the principal from the balance.
$618 - $600 = $18
2.Use the simple interest formula and solve for r.
I = Prt
18= 600 x r x (1/2)
r= 0.06 =6%
Let the rate be R% p.a.
I gives, P = Rs. 8000 and T = 4 years.
II gives, S.I = Rs. (8800 - 8000) = Rs. 800.
R = [100 x S.I] / [p x t ]= (100 x 800)/(8000 x 4) = 2 ½ % p.a
Thus, I and II both are needed to get the answer.
We know that, R = (100 x S.I) / (P x T)
Now I gives, S.I = Rs. 4000.
II gives, T = 4 years.
But, P is unknown. So, we cannot find R.
So, given data is insufficient to get R.
I = (P x T x R) /100
total interest=1187.50*6
Total cost = deposit + instalment amount × number of instalments
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