P = Rs. 900, R = 3 ½ % = 7/2 %, T = 2 years.
Therefore,
S.I. = PTR/100
S.I. = Rs. (900 x 7/2 x 2/100) = Rs. 63
Now, P = Rs. 200, S.I. = Rs. 63, R = 5 %
Time = ((100 x 63) / (200 x 5) ) years = 6.3 years.
I = (600x11x5)/100 = 330 Paise = Rs. 3.30
Given,
S.I = 3 Principal Amount
=> 3A = A x 16 x R/100
By solving, we get
=> R = 18.75%
Let the two different rates of interests be r1 and r2 respectively.
From the given data,
Hence, the difference in the interest rates = 3.87
Present worth = 169/(1+4/100)^n = 156.25
Given : S.I. = Rs. 50.
I gives, R = 10% p.a.
II gives, T = 10 years.
Sum = (100 x S.I)/(t x r ) = Rs.(100 x 50)/(10 x 10) = Rs.50
I=
I=prt
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