Discussion
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- Question
A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ?
Options- A. 400
- B. 600
- C. 900
- D. 700
- Correct Answer
- 900
Explanation6,400 gents, 2400 ladies in that company.
So total 8,800employees.
for 8,800 employees, we want 2400 ladies.
for 12,100employees we want how many ladies ?
=> (12,100/8,800) x 2400 = 3300.
So we want 3300 - 2400 = 900 more ladies. - 1. If k : l = 4 : 3 and l : m = 5 : 3, then find k : l : m ?
Options- A. 18 : 24 : 11
- B. 9 : 15 : 1
- C. 20 : 15 : 9
- D. 21 : 7 : 3 Discuss
- 2. The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of ?
Options- A. 4:5
- B. 6:5
- C. 3:2
- D. 1:3 Discuss
- 3. What is the equivalent compound ratio of 5:6::7:10::6:5 ?
Options- A. 7 : 9
- B. 9 : 7
- C. 7 : 4
- D. 7 : 10 Discuss
- 4. At a casino in mumbai, there are three tables A, B and C. The payoffs at A is 10:1, at B is 20:1 and at C is 30:1. If a man bets Rs 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be?
Options- A. Rs.2500
- B. Rs.2000
- C. Rs.4000
- D. None of these Discuss
- 5. A, B and C have amounts in the ratio of 3 : 4 : 5. First B gives 1/4th to A and 1/4th to C then C gives 1/6th to A. Find the final ratio of amount of A, B and C respectively.
Options- A. 4:3:5
- B. 5:4:3
- C. 3:4:5
- D. 5:2:5 Discuss
- 6. If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:
Options- A. Rs. 408
- B. Rs. 204
- C. Rs. 412
- D. Rs. 220 Discuss
- 7. A sum is divided among K, L and M in such a way that for each rupee K gets, L gets 45 paisa and M gets 30 paisa. If the share of L is Rs. 27, what is the total amount ?
Options- A. Rs. 159
- B. Rs. 96
- C. Rs. 147
- D. Rs. 105 Discuss
- 8. Pooja, Shipra and Mounika are three sisters .Pooja and Shipra are twins. The ratio of sum of the ages of Pooja and Shipra is same as that of Mounika alone. Three years earlier the ratio of age of Pooja and Mounika was 2:7 . what will be the age of Shipra 3 years hence?
Options- A. 21 years
- B. 16 years
- C. 8 years
- D. 12 years Discuss
- 9. Total number of students in 3 classes of a school is 333 . The number of students in class 1 and 2 are in 3:5 ratio and 2 and 3 class are 7:11 ratio . What is the strength of class that has highest number of students ?
Options- A. 125
- B. 155
- C. 135
- D. 165 Discuss
- 10. At a game of billiards, A can give B 20 points in 60 and A can give C 15 points in 60. How many points can C give B in a game of 90 ?
Options- A. 9 points
- B. 10 points
- C. 11 points
- D. 8 points Discuss
Ratio and Proportion problems
Search Results
Correct Answer: 20 : 15 : 9
Explanation:
Given k : l = 4 : 3
l : m = 5 : 3
Then k : l : m = 20 : 15 : 9
Correct Answer: 6:5
Explanation:
4:5
3:2
-------
=> 12:15:10
12:10
=> 6:5
Correct Answer: 7 : 10
Explanation:
Given 5:6 :: 7:10 :: 6:5
We know that compound ratio is calculated as
a:b :: c:d :: e:f
(axcxe):(bxdxf)
=> (5x7x6):(6x10x5)
=> (210):(300)
= 7:10
Correct Answer: Rs.4000
Explanation:
Maximum earning will be only when he will won on the maximum yielding table.
A ----> 10:1
B ----> 20:1
C ----> 30:1
i.e, he won on B and C but lost on A
20 x 200 + 30 x 200 -1 x 200 = 9800
minimum earning will be when he won on table A and B and lose on that table 3.
Therefore, 10 x 200 + 20 x 200 - 1 x 200 = 6000-200 = 5800
Therefore, Difference= 9800 - 5800 = 4000
Correct Answer: 5:2:5
Explanation:
A B C
3x 4x 5x
(3x+x) 2x (5x+x) (B Gives 1/4 to A and 1/4 to C)
=4x 2x 6x
(4x+x) 2x 5x ( C Gives 1/6 to A)
=5x 2x 5x
Therefore, 5 : 2 : 5
Correct Answer: Rs. 204
Explanation:
Given ratio = 1/2:2/3:3/4 = 6:8:9
1st part = 782 x 6/23 = Rs. 204.
Correct Answer: Rs. 105
Explanation:
K : L : M = 100 : 45 : 30
= 20 : 9 : 6
Given L share is 27
=> 9 ------ 27
35 ------ ?
=> 105
Correct Answer: 8 years
Explanation:
Since Pooja and Shipra are twins so their ages be same. Let their ages be x and age of Mounika be y , then
x+x = y -------(1)
and
Now, from equation (1),
7x - 4x = 15 => x = 5
So the age of Shipra 3 years hence will be 5+3 = 8 years
Correct Answer: 165
Explanation:
Ratio C1:C2 = 3:5 and C2:C3 = 7:11
So C1:C2:C3 = 21 : 35 : 55
Let the strength of three classes are 21x, 35x and 55x respectively, then
Given that 21x + 35x + 55x = 333
=> 111x = 333 or x=3
So strength of the class with highest number of students =55x = 55x3 = 165.
Correct Answer: 10 points
Explanation:
a:b = 60:40
a:c = 60:45
c/a x a/b = 45/60 x 60/40 = 45/40 = 90/80
So C gives B => 10 points.
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