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At a casino in mumbai, there are three tables A, B and C. The payoffs at A is 10:1, at B is 20:1 and at C is 30:1. If a man bets Rs 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be?

Correct Answer: Rs.4000

Explanation:

Maximum earning will be only when he will won on the maximum yielding table.


     A ----> 10:1


     B ----> 20:1


     C ----> 30:1


 i.e, he won on B and C but lost on A


 20 x 200 + 30 x 200 -1 x 200 = 9800


 minimum earning will be when he won on  table A and B and lose on that table 3.


 


Therefore, 10 x 200 + 20 x 200 - 1 x 200  =  6000-200 = 5800


Therefore, Difference= 9800 - 5800 = 4000


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