Maximum earning will be only when he will won on the maximum yielding table.
A ----> 10:1
B ----> 20:1
C ----> 30:1
i.e, he won on B and C but lost on A
20 x 200 + 30 x 200 -1 x 200 = 9800
minimum earning will be when he won on table A and B and lose on that table 3.
Therefore, 10 x 200 + 20 x 200 - 1 x 200 = 6000-200 = 5800
Therefore, Difference= 9800 - 5800 = 4000
A B C
3x 4x 5x
(3x+x) 2x (5x+x) (B Gives 1/4 to A and 1/4 to C)
=4x 2x 6x
(4x+x) 2x 5x ( C Gives 1/6 to A)
=5x 2x 5x
Therefore, 5 : 2 : 5
Let the quantity of alcohol and water be 4x liters and 3x liters respectively. Then,
(4x)/(3x+5) = 4/5
=> 20x = 4(3x+5)
=> x = 2.5
Quantity of alcohol = (4 * 2.5) liters = 10 liters.
504/M = 384/800
(504 x 800) / 384 = M
M = 1050
Given the salaries are in the ratio of 4 : 5 : 6
Now the salaries are increased by 50%, 60% and 50% respectively
The New ratio of salaries will be
4 x (150/100) : 5 x (160/100) : 6 x (150/100)
= 6 : 8 : 9
The new ratio of salaries of Akhil, Arun and Karthik is 9 : 8 : 6
Given total applicants = 135
Given graduates are G=60
Otherthan graduates=135-60 = 75
Given experienced candidates = 80
1) For maximum number of graduates have experience
Total graduates to have experience = 60
2) For minimum number of graduates have experience
Remaining after taking other than graduates in experience= 80-75 = 5
Given 5:6 :: 7:10 :: 6:5
We know that compound ratio is calculated as
a:b :: c:d :: e:f
(axcxe):(bxdxf)
=> (5x7x6):(6x10x5)
=> (210):(300)
= 7:10
4:5
3:2
-------
=> 12:15:10
12:10
=> 6:5
Given k : l = 4 : 3
l : m = 5 : 3
Then k : l : m = 20 : 15 : 9
6,400 gents, 2400 ladies in that company.
So total 8,800employees.
for 8,800 employees, we want 2400 ladies.
for 12,100employees we want how many ladies ?
=> (12,100/8,800) x 2400 = 3300.
So we want 3300 - 2400 = 900 more ladies.
Given ratio = 1/2:2/3:3/4 = 6:8:9
1st part = 782 x 6/23 = Rs. 204.
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