To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres.
=> the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres
However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity.
i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.
Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
22 | 1 | days |
2 |
22 | 1 | days |
2 |
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes | ❨ | 3 | x 60 | ❩ | = 90 days. |
2 |
So, A takes 30 days to do the work.
A's 1 day's work = | 1 |
30 |
B's 1 day's work = | 1 |
90 |
(A + B)'s 1 day's work = | ❨ | 1 | + | 1 | ❩ | = | 4 | = | 2 |
30 | 90 | 90 | 45 |
∴ A and B together can do the work in | 45 | = 22 | 1 | days. |
2 | 2 |
Distance between Raipur and Somgarh
= Average speed x Time
= 69 x 35/60= 161/4 km
New speed = (69 + 36) km/h = 105 km/h
? Time = Distance/ Speed = 161/4 x 105 h
= 161 x 60/4 x 105min = 23 min
Let the number of soldiers transferred be N
Now, the food would last for 25 days for (2000 - N) soldiers.
Less men, More days (indirect proportion)
25 : 20 : : 2000 : (2000 - N)
? 2000 - N = (2000 x 20)/25
? 2000 - N = 1600
? N = 2000 - 1600 = 400
The required greatest number is the HCF of (263 - 7, 935 - 7, 1383 - 7)
i.e., HCF of 256, 928 and 1376 = 32
Let the number be 16a and 16b, where a and be are two number prime to each other.
? 16a x 16b = 7168
? ab = 28
Now, the pairs of number whose products is 28, are (28, 1) : (14, 2), (7,4)
14 and 2 which are not prime to each other should be rejected.
Hence, the required answer
= (448 + 16) + (112 + 64) = 640
In a 800 meter race, A covers 800 meter while B cover 760 meter.
? A covers 200 m while B will cover 760 x 200 / 800 = 190 m
Again, B covers 500 m while C 495 m
? B covers 190 m while C will cover = 495 x 190 / 500 = 188.10 m
Since, A covers 200 m while C 188.10 m
Hence, A will beat C by (200 ? 188.10) = 11.9 m
Given. ratio = 7/2 : 4/3 : 6/5
= (7/2) x 30 : (4/3) x 30 : (6/5) x 30
= 105 : 40 : 36
Let investment of Amitabh = 105k
Investment of Kamlesh = 36k
Ratio of their investments
= [105k x 4 + 150% x8 of 105k] : (40k x 12) : (36k x 12)
= (420k + (150/100) x 105k x 8) : (480k) : (432k)
= (1680k) : (480k) : (432k)
= 35 : 10 : 9
? Brijesh's share
= (21600 x 10) / (35 + 10 + 9)
= (21600 x 10) / 54
= ? 4000
As per given question,
In 1 minute, 6 identical machines can produce a total of 270 bottles.
In 1 minute, 1 identical machines can produce a total of 270 / 6 bottles.
In 1 minute, 10 identical machines can produce a total of 270 x 10 / 6 bottles.
In 4 minute, 10 identical machines can produce a total of 270 x 10 x 4 / 6 bottles.
In 4 minute, 10 identical machines can produce a total of 45 x 10 x 4 bottles.
In 4 minute, 10 identical machines can produce a total of 1800 bottles.
Let money lent at 12% Rs. P
Then, money lent at 121/2% = Rs. (2540 - P )
? (P x 12 x 1)/100 + {(2540 - P) x 25/2 x 1}/100 = 311.60
? 3P/25 + 2540 - P/8 = 311.60
? 24P + 25(2540 - P) = 200 x 311.60
? P = 63500 - 62320 = 1180
160 = ?1600 x B.G.
? B.G. = (160 x 160)/1600 = Rs. 16
? Banker's discount = 160 + 16 = Rs. 176
[? B.D. = T.D. + B.G.]
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.