To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres.
=> the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres
However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity.
i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.
Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
Here sum is put on compound interest,
? P.W. = A / (1 + r / 100)n = 2420 / (1 + 10 / 100)2 = 2420 x 100 / 121 = Rs. 2000
? T.D. = P.W. - P
? True discount = 2420 - 2000 = Rs. 420
The Sum of the digits in each number, Except 324 is 10.
The given number series follows the pattern that,
24×0 + 4 = 4
4×1 + 9 = 13
13×2 + 16 = 42
42×3 + 25 = 151
151×4 + 36 = 640
Therefore, the odd number in the given series is 41
From the beginning, the next term comes by adding prime numbers in a sequence of 2, 3, 5, 7, 9, 11, 13... to its previous term. But 165 will not be in the series as it must be replaced by 166 since 153+13 = 166.
The given number series follows a pattern that
196, 169, 144, 121, 100, 81, ?
-27 -25 -23 -21 -19 -17
=> 81 - 17 = 64
Therefore, the series is 196, 169, 144, 121, 100, 81, 64.
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