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- Question
Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ?
Options- A. 108
- B. 107
- C. 109
- D. 110
- Correct Answer
- 109
ExplanationFrom given data,
R : M = 5 : 7
M : A = 5 : 7
R : M : A = 25 : 35 : 49
25 + 35 + 49 = 109
- 1. Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats ?
Options- A. 1 : 2 : 3
- B. 2 : 3 : 4
- C. 3: 4 : 5
- D. 4 : 5 : 6 Discuss
- 2. Two vessel P and Q contain milk and water in ratio 3 : 2 and 5 : 3 respectively. If 10 liters of the mixture is removed from vessels P and poured in vessel Q then ratio of milk to water in vessel Q becomes 8 : 5. Find the initial quantity of water in vessel Q.
Options- A. 10 lit
- B. 6 lit
- C. 16 lit
- D. 12 lit Discuss
- 3. Rs. 2600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4 ?
Options- A. 600
- B. 300
- C. 150
- D. 75 Discuss
- 4. Paint needs to be thinned to a ratio of 2 parts paint to 1.5 parts water. The painter has by mistake added water so that he has 6 litres of paint which is half water and half paint. What must he add to make the proportions of the mixture correct?
Options- A. 1 litre paint
- B. 1 litre water
- C. ½ litre water and one litre paint
- D. ½ litre paint and one litre water Discuss
- 5. If 12 men can reap 120 acres of land in 36 days, how many acres of land can 54 men reap in 54 days?
Options- A. 710 acres
- B. 760 acres
- C. 810 acres
- D. 860 acres Discuss
- 6. There are two containers, the first one contains 1 litre pure water and the second one contains 1 litre pure milk.Now 5 cups of water from the first container is taken out is mixed well in the second container. Then, 5 cups of this mixture is taken out and is mixed in the first container. Let A denote the proportion of milk in the first container and B denote the proportion of water in the second container then:
Options- A. A
- B. A=B
- C. A>B
- D. can't be determined Discuss
- 7. Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ?
Options- A. 7 : 12
- B. 8 : 13
- C. 9 : 4
- D. 2 : 5 Discuss
- 8. 64 boys and 40 girls form a group for social work. During their membership drive, the same number of boys and girls joined the group. How many members does the group have now, if the ratio of boys to girls is 4:3 ?
Options- A. 168
- B. 201
- C. 147
- D. 154 Discuss
- 9. The ratio of students in a coaching preparing for B.tech and MBA is 4 : 5. The ratio of fees collected from each of B.tech and MBA students is 25 : 16. If the total amount collected from all the students is 1.62 lakh, what is the total amount collected from omly MBA aspirants?
Options- A. Rs. 62,000
- B. Rs. 72,000
- C. Rs. 82,000
- D. None of these Discuss
- 10. A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ?
Options- A. 1:3
- B. 2:1
- C. 3:2
- D. 2:3 Discuss
Ratio and Proportion problems
Search Results
Correct Answer: 2 : 3 : 4
Explanation:
Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8.
Seats for Mathematics, Physics and Biology in a school are 5x, 7x and 8x.
There is a proposal to increase these seats by 40%, 50% and 75% respectively.
Then Seats for Mathematics, Physics and Biology in a school will be
1.4 X 5x, 1.5 X 7x and 1.75 X 8x and
ratio will be 7 : 10.5 : 14 => 2:3:4.
Correct Answer: 10 lit
Explanation:
Given ratio of initial mixture of milk and water in Q = 5 : 3
Let the initial quantity of mixture in vessel Q = 8x
Let quantity of Milk = 5x and
Let quantity of water = 3x
According to the question,
=> 25x + 30 = 24x + 32
=> x = 2
Required Initial quantity of milk = 5x = 5 x 2 = 10 lit.
Correct Answer: 600
Explanation:
1/2:1/3:1/4 = 6:4:3
As the difference is 3
=> 3/13x2600 = 600
Correct Answer: 1 litre paint
Explanation:
At the moment the paint is 3 liters of paint and 3 liters of water. We need to add to this to make the new ratio 2 liters paint to 1.5 liters water. As this is equivalent to 4 : 3 we can see that we have the right amount of water, and just need 1 liter of paint to make it correct.
Correct Answer: 810 acres
Explanation:
As 12 men can reap 120 acres, 54 men will be able to reap more acres in 36 days, 120 acres of land was reaped, so in 54 days, more land will be reaped.
Thus, the numbers of acres that can be reaped by 54 men in 54 days = = 810 acres
Correct Answer: A=B
Explanation:
Here the ratio of mixtures( i.e milk , water) doesnot matter. But the important point is that whether the total amount ( either pure or mixture ) being transferred is equal or not.Since the total amount ( i.e 5 cups) being transferred from each one to another , hence A =B.
Correct Answer: 8 : 13
Explanation:
To get the solution that contains 1 part of milk and two parts of water,
they must be mixed in the ratio as
7x+6x/5y+11y = 1/2
26x = 16y
x/y = 16/26
x/y = 8/13
Correct Answer: 168
Explanation:
Let us say x boys and x girls joined the group.
(64 + x)/(40 + x) = 4/3
192 + 3x = 160 + 4x => x = 32
Number of members in the group = 64 + x + 40 + x
= 104 + 2x = 168.
Correct Answer: Rs. 72,000
Explanation:
The ratio of fees collected from B.Tech : MBA = 4x * 25y : 5x * 16y
= 100xy : 80xy
= 5xy : 4 xy = 5k : 4k
The amount collected only from MBA students = = Rs. 72,000
Correct Answer: 3:2
Explanation:
Let us assume S as number of shirts and T as number of trousers
Given that each trouser cost = Rs.70 and that of shirt = Rs.30
Therefore, 70 T + 30 S = 810
=> 7T + 3S = 81......(1)
T = ( 81 - 3S )/7
We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of T
Simplifying by taking 3 as common factor i.e, 3(27-S) / 7
In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7
Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9
Hence for S, put T in eq(1), we get
S = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.
The ratio of T:S = 9:6 = 3:2.
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