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- Question
Salaries of Ravi and Sumit are in the ratio 2:3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40:57. What is Sumit's salary?
Options- A. 38000
- B. 46800
- C. 36700
- D. 50000
- Correct Answer
- 38000
ExplanationLet the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then,
(2x+4000) / (3x+4000) = 40 / 57
? 57 × (2x + 4000) = 40 × (3x+4000)
? 6x = 68,000
? 3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000 - 1. Two years ago, a mother was four times as old as her daughter. 8 years later, mother's age will exceed her daughter's age by 12 years. The ratio of the present ages of mother and daughter is?
Options- A. 3 : 1
- B. 4 : 1
- C. 3 : 2
- D. 5 : 1 Discuss
- 2. Five years ago, the total of the ages of father and son was 60 years. The ratio of their present ages is 4 : 1. Then the present age of the father is?
Options- A. 48 years
- B. 51 years
- C. 56 years
- D. 61 years Discuss
- 3. A is as much younger than B as he is older then C. If the sum of B's and C's age is 40 years. Find the age of A.?
Options- A. 20 years
- B. 25 years
- C. 30 years
- D. 27 years Discuss
- 4. A says to B "I am twice as old as you were when I was as old as you are." The sum of their ages is 63 years. Find the difference of their ages?
Options- A. 27 years
- B. 12 years
- C. 9 years
- D. 6 years Discuss
- 5. The product of the ages of Harish and Seema is 240 . If twice the age of seema is more then Harish's age by 4 years. What is seema's age in years?
Options- A. 12 years
- B. 20 years
- C. 10 years
- D. 14 years Discuss
- 6. After 6 years Pradhan's age will be 3/7 times the age of his father. 10 years ago the ratio in the age of Pradhan and his father was 1 : 5. What is the present age of Pradhan's father?
Options- A. 40 years
- B. 50 years
- C. 56 years
- D. Data is inadequate Discuss
- 7. The ratio between present age of Kunal and Ganesh is 3 : 5. If 4 years later Kunal will be younger then Ganesh by 12 years. What is the present age of Kunal?
Options- A. 17 years
- B. 19 years
- C. 22 years
- D. None of these Discuss
- 8. The average age of 9 students and their teacher is 16 yr. The average age of the first four students is 19 yr and that of the last five is 10 yr. The teacher's age is?
Options- A. 36 yr
- B. 34 yr
- C. 30 yr
- D. 28 yr Discuss
- 9. At present, the ratio of the ages of Maya and Chhaya is 6 : 5 and fifteen years from now, the ratio will get changed to 9 : 8. Maya's present age is?
Options- A. 21 yr
- B. 24 yr
- C. 30 yr
- D. 40 yr Discuss
- 10. At the present, Palash is three times Arnav's age. After 7 yr, Palash will be twice Arnav's age, then how many times will Palash's age be in another 14 yr time with respect to Arnav's age then?
Options- A. 1
- B. 3
- C. 2
- D. 1.5 Discuss
More questions
Correct Answer: 3 : 1
Explanation:
Let the mother's age 2 years ago be 4x and daughter's age 2 years ago be be x.
? (4x + 8) - (x + 8) = 12
? 3x = 12
? x = 4
? Mother's present age = 4x + 2 = 18 years
and daughter's present age = x + 2 = 6 years
? Required ratio = 3 : 1
Correct Answer: 56 years
Explanation:
Let the present age of the son be x and that of the father be 4x years.
? (x - 5) + (4x - 5) = 60
? 5x = 70
? x = 14 years
? Father's present age = 4x = 56 years
Correct Answer: 20 years
Explanation:
Age of C < Age of A < Age of B
From question,
A = C + x ....(i)
B = A + x ....(ii)
From equation (i) and (ii)
A - B = C - A
? 2A = B + C
? A = (B + C) / 2
Given that sum of the ages of B and C is 40 years.
So, A = (B + C) / 2 = 40/2 = 20 Years
Correct Answer: 9 years
Explanation:
Let the present age of A is x and present age of B is y.
Therefore, x + y = 63 ....(i)
Difference of their ages is = (x - y) years.
When A was as old as B then, A's age was 'y; years and B's age was [y - (x - y)] = (2y - x) years.
Given that present age of A is twice the past age of B.
? x = 2(2y - x)
? 3x = 4y .....(ii)
From (i) and (ii)
x = 36 and y = 27
So the difference in age of A and B is 36 - 27 = 9 years.
Correct Answer: 12 years
Explanation:
Let the ages of Harish and Seema be x and y respectively.
According to the question,
xy = 240 ....(i)
2y - x = 4 ....(ii)
Solving equations (i) and (ii), we get
y = 12 years
Correct Answer: 50 years
Explanation:
Let the present age of Pradhan be P years and his father's age = Q years.
From 1st condition,
(P + 6) = (Q + 6 ) x 3/7
? 7P + 42 = 3Q + 18
? 7P - 3Q = -24 ...(i)
From 2nd condition
(P - 10) / (Q - 10) = 1/5
? 5P - 50 = Q - 10
? 5P - Q = 40 .....(ii)
Multiplying equation (ii) by 3 and subtracting from (i) we get
P = 18, Q = 50
So present age of Pradhan's father = 50 years.
Correct Answer: None of these
Explanation:
Let the present age of Kunal be 3x year and the
present age of Ganesh = 5x years.
According to question ,
(5x + 4 ) - (3x + 4 ) = 12
? 2x = 12
? x = 6
? Present age of Kunal = 3x = 3 x 6 = 18 year
Correct Answer: 34 yr
Explanation:
? Total age of 9 students and a teacher = 10 x 16 = 160 yr
Total age of first 4 students = 4 x 19 = 76 yr
and total age of last 5 students = 5 x 10 = 50 yr
? Age of teacher = 160 - 76 - 50 = 34 yr
Correct Answer: 30 yr
Explanation:
Let the present ages of Maya and Chhaya are 6N and 5N yr. respectively.
According to the question, After 15 yr,
(6N + 15) / (5N + 15) = 9/8
? 48N + 120 = 45N + 135
? N = 5
Hence, present age of Maya = 5 x 6 = 30 yr
Correct Answer: 1
Explanation:
Let Arnav's age = k yr
Then, Palash's age = 3k yr
Acoording to the question, 3k + 7 = 2(k + 7)
? 3k + 7 = 2k + 14
? k = 7
? Age of Arnav after 14 yr = 7 + 14 = 21 yr
and Palash's present age = 21 yr
Hence, Palash's age is one time of Arnav's age .
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