The cost price of three varieties of mangoes namely M, N and O is Rs. 20/kg, Rs. 40/kg and Rs. 50/kg respectively. Find the selling price of one kg of mango in which these three varieties of mangoes are mixed in the ratio of 2 : 3 : 5 such that there is a net profit of 20%?

Correct Answer: 100%

Explanation:

When 3 passengers income was 3x
expense= Rs.30 
profit =20% of 30 = Rs.6 
That means his earning is Rs.36. so that per passenger fare must be Rs.12.

When 4 passengers
earning = 12x4=Rs.48.
expense =Rs.24.
profit = Rs.24 = 100%

Correct Answer: 14.28 % profit

Explanation:

Let 1kg of Rs. 100 then 840gm is of Rs. 84.
Now (label on can 1kg but contains 840kg ) so for customer it is of Rs. 100 and further gives 4% discount [he sells his article on 4% loss on cost price.]
So now S.P = Rs. 96
But actually it contains 840 gm so C.P for shopkeeper = Rs. 84
S.P = Rs. 96
C.P = Rs. 84
Profit% = {(S.P-C.P)/C.P}x100
{(96-84)/84} x 100 = 14.28571429% PROFIT.

Correct Answer: Rs. 3250

Explanation:

Let the Cost price of the powerbank = Rs. P

But given that by selling it at Rs. 1950, it gives a loss of 25%

=> P x 75 100 = 1950
=> P = 1950 x 100 75 = Rs. 2600
Now, to get a profit of 25%

Selling Price = 2600 x 125 100 = Rs . 3250.

Correct Answer: 20%

Explanation:

Given

      125% ---- 3400

=> 100% ---- ?

=> ? = 3400x100/125 = 2720

=> Cost price of the article = Rs. 2720

Profit when article sold at Rs. 3265 = 3265 - 2720 = 545

Hence, Profit% = Gain x 100/cost price

=> P% = 545 x 100/2720

=> P% = 20%

Correct Answer: 30%

Correct Answer: 4%

Explanation:

loss % =  c o m m o n g a i n o r l o s s 10 2 %

 

           = (20/10)x(20/10)% = 4%

Correct Answer: Rs. 60

Explanation:

Let the cost price of a ball is Rs.x
Given, on selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls
The equation is :
17x - 720 = 5x
Solving the equation
we get x = 60
Therefore, cost price of a ball is Rs. 60.

Correct Answer: Rs. 404.80

Explanation:

Let C1 be the cost price of the first article and C2 be the cost price of the second article.
Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%.

We know, C1 + C2 = 600.
The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1
The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2.

The total selling price of the first and second article = 1.22C1 + 0.92C2.

As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2.

Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600
As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get
1.22C1 + 0.92(600 - C1) = 600
or 1.22C1 - 0.92C1 = 600 - 0.92*600
or 0.3C1 = 0.08*600 = 48
or C1 = 48/(0.3) = 160.
If C1 = 160, then C2 = 600 - 160 = 440.
The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.

Correct Answer: Rs. 400

Explanation:

Let the cost price of the fruits be 'C.P'

From the given data, after analysis it can be solved as

(121% of C.P) - (125% of 91% of C.P) = 29

$$\begin{gathered} 121 100 C . P - 125 100 x 91 100 x C . P = 29 \\ 121 100 - 125 x 91 100 x 100 C . P = 29 \\ ( 12100 - 125 x 91 ) C . P = 290000 \\ ( 12100 - 11375 ) C . P = 290000 \\ 725 C . P = 290000 \\ C . P = 400 \end{gathered}$$

 

Hence, the cost price of the fruits = Rs. 400.

 

Correct Answer: 40%

Explanation:

Cost price = Rs. 30

Selling price = Rs. 50

Gain = Rs. 20

Profit % = Gain/cost price x 100 = 20/50 x 100 = 40%