Let 1kg of Rs. 100 then 840gm is of Rs. 84.
Now (label on can 1kg but contains 840kg ) so for customer it is of Rs. 100 and further gives 4% discount [he sells his article on 4% loss on cost price.]
So now S.P = Rs. 96
But actually it contains 840 gm so C.P for shopkeeper = Rs. 84
S.P = Rs. 96
C.P = Rs. 84
Profit% = {(S.P-C.P)/C.P}x100
{(96-84)/84} x 100 = 14.28571429% PROFIT.
Let the Cost price of the powerbank = Rs. P
But given that by selling it at Rs. 1950, it gives a loss of 25%
=>
=>
= Rs. 2600
Now, to get a profit of 25%
Selling Price = .
Given
125% ---- 3400
=> 100% ---- ?
=> ? = 3400x100/125 = 2720
=> Cost price of the article = Rs. 2720
Profit when article sold at Rs. 3265 = 3265 - 2720 = 545
Hence, Profit% = Gain x 100/cost price
=> P% = 545 x 100/2720
=> P% = 20%
Let marked price = Rs. 100.
Then, C.P. = RS. 54,
S.P. = Rs. 85
Gain % = 31/64 x 100 = 48.4%.
C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.
When 3 passengers income was 3x
expense= Rs.30
profit =20% of 30 = Rs.6
That means his earning is Rs.36. so that per passenger fare must be Rs.12.
When 4 passengers
earning = 12x4=Rs.48.
expense =Rs.24.
profit = Rs.24 = 100%
Total cost of all varieties of mangoes = 20 x 2 + 40 x 3 + 50 x 5 = 40 + 120 + 250 = Rs. 410
Then, cost of 1 kg mangoes = 410/10 = Rs. 41
To get 20% profit,
The rate at which the mangoes should be sell = 120/100 x 41 = Rs. 49.2
loss % = %
= (20/10)x(20/10)% = 4%
Let the cost price of a ball is Rs.x
Given, on selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls
The equation is :
17x - 720 = 5x
Solving the equation
we get x = 60
Therefore, cost price of a ball is Rs. 60.
Let C1 be the cost price of the first article and C2 be the cost price of the second article.
Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%.
We know, C1 + C2 = 600.
The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1
The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2.
The total selling price of the first and second article = 1.22C1 + 0.92C2.
As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2.
Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600
As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get
1.22C1 + 0.92(600 - C1) = 600
or 1.22C1 - 0.92C1 = 600 - 0.92*600
or 0.3C1 = 0.08*600 = 48
or C1 = 48/(0.3) = 160.
If C1 = 160, then C2 = 600 - 160 = 440.
The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.