When the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 litres of milk.
Since, the profit % =
Therefore, profit percentage = = 25%
cost price = (225 + 15) = 240 sell price = 300
gain = (60/240)*100 = 25%
CP = 100, SP (with tax) =120
New SP = 100 - 5 = 95
Effective discount = 120 - 95 = 25
So, at SP of 95 ----> discount = 25
and at SP of 3325 -----> discount =
Given M.P=45,S.P=42, Profit = 0.05
Let C.P=x , Then
Profit = (42-x)/x = 0.05
=> x = 40.
Loss%= (common gain or loss % / 10)2 = (10/10)² % = 1%.
Total investment = Rs. (120 * 80 + 280 + (40/100) * 120 + 72).
= Rs. (9600 + 280+48 + 72) = Rs, 10000.
Sell price of 120 reams = 108% of Rs. 10000 = Rs. 10800.
Sell Price per ream = Rs. [10800/120] = Rs. 90.
Let C.P. = Rs. C.
Then, 832 - C = C - 448
2C = 1280 => C = 640
Required S.P. = 150% of Rs. 640 = 150/100 x 640 = Rs. 960.
Tota profit percentage = (119 x 100/85) - 100 = 3400/85 = 40%
Let the shopkeeper buy 300g for Rs.300. Now he sells 100g for Rs.110, another 100g for Rs120, and the rest 100g for Rs94.
Therefore, the total amount he receives = Rs.110 + Rs.120 + Rs.94 = 324.
Therefore, the shopkeeper spends Rs.300 and gets back Rs.324.
Therefore, his profit percentage = % = 8%
Cost price of 25 kg = Rs. (15 x 14.50 + 10 x 13) = Rs. 347.50.
Sell price of 25 kg = Rs. (25 x 15) = Rs. 375.
profit = Rs. (375 ? 347.50) = Rs. 27.50.
Let cp= 100,
35 % increase in sp=135
10 % discount in 135((135*10)/100)=13.5
so 1st sp=(135-13.5)=121.5, again 15 % discount in 1st sp((121.5*15)/100)=18.225
2nd sp=(121.5-18.225)=103.275,
so finally cp=100,sp=103.275 ,gain by 3.27%
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