Initially CP profit SP MP
100 x (100+x) 133.33
After Change 100 2x (100+x)
Now, Since (100+x) - 100 = 2x
x= 20%
CP Profit SP MP
100 20 120 133.33
So, 300 60 360 400
Again 300 120 420
So the increased selling price = Rs. 420
Total cost of 4 cars = 1+2 = 3 lakh
Total S.P of 4 cars = 3 x 1.5 = 4.5 lakh ( )
S.P of 1 car = 1.2 lakh
S.P of rest 3 cars = 4.5 - 1.2 = 3.3 lakh
Average S.P of all the 3 cars = 1.1 lakh
Let the cost of Production = Rs. P
Then, as per question,
=1265
=> P=800
SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Let the new S.P be x, then
(100 - loss%) : (1st S.P.) = (100 + gain%) : (2nd S.P.)
=> x = 1260
Let original Cost price is x
Its Selling price = (105/100) * x = 21x/20
New Cost price = (95/100) * x = 19x/20
New Selling price = (110/100 )* (19x/20 )= 209x/200
[(21x/20) - (209x/200)] = 1
=> x = 200
A B C
investment 3x 4x 5x
Rate of return 6y% 5y% 4y%
Return
Total = (18+20+20) =
B's earnings - A's earnings = = 250
Total earning = = 7250
SP of first article = Rs.1000
Profit = 20%
SP of Second Article = Rs.1000
Loss = 20%
So, Total SP = Rs.2000; Total CP = Rs.6250/3
As the CP is more than SP, he makes a loss.
Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3)
So, Loss Percent = Lossx100/CP = 4%
33.33% profit means there is one part water and 3 part is pure wine. so the required ratio of water and wine in the mixture is 1:3
Cost Price of 5 kg = Rs.(14*2 + x*3) = (28 + 3x).
Sell price of 5 kg = Rs. (22x5) = Rs. 110.
[{110 - (28 + 3x)}/(28 + 3x) ]* 100 =10
[82-3x/28 + 3x]= 1 / 10
820 - 30x = 28 +3x
33x = 792
x = 24
110% of S.P. = Rs. 616
S.P. = (616 x 100)/110 = Rs. 560
C.P = (110 x 560)/112 = Rs. 500
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