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- Question
An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ?
Options- A. 21.4 and 42.8
- B. 25.2 and 50.4
- C. 31.4208 and 62.8416
- D. 33.12 and 66.24
- Correct Answer
- 31.4208 and 62.8416
ExplanationBirds speeds in mtrs/sec is 'x' and '2x' .
While flying from Engine to end, relative speed = (x+10) m/sec
from end to engine, flying speed = (2x - 10) mtr/sec
so
1000/(x+10) + 1000/(2x-10) = 187.5 secs
solving it, we get
so x = 8.728 m/sec and 2x= 17.456 m/secx = 31.4208 km/hr and 2x = 62.8416 km/hr.
- 1. Agra and Delhi are 160 km apart. A train leaves Agra for Delhi and at the same time another train leaves Delhi for Agra. Both the trains meet 5 hrs after they start moving. If the train travelling from Agra to Delhi travels 6 km/hr faster than the other train, find the speed of the faster train?
Options- A. 19 kmph
- B. 13 kmph
- C. 7 kmph
- D. 9 kmph Discuss
- 2. The length of two superfast trains are 140 mts and 160 mts respectively. If they run at the speed of 60 km/hr and 80 km/hr respectively in opposite direction, find the time in which they will cross each other ?
Options- A. 7.71 sec
- B. 10.48 sec
- C. 9.36 sec
- D. 8.45 sec Discuss
- 3. A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Options- A. 5
- B. 6
- C. 7
- D. 10 Discuss
- 4. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is ?
Options- A. 45 kmph
- B. 25 kmph
- C. 30 kmph
- D. 50 kmph Discuss
- 5. Two trains namely X & Y leave station 'A' at 6.30am and 7.40am and travel at 30km/hr and 40 km/hr respectively. How many kms from 'A' will the trains meet ?
Options- A. 140 kms
- B. 120 kms
- C. 96 kms
- D. 142 kms Discuss
- 6. Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is ?
Options- A. 387 kms
- B. 242 kms
- C. 145 kms
- D. 444 kms Discuss
- 7. Two trains of equal length, running with the speeds of 60 and 40 kmph, take 50 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions ?
Options- A. 10 sec
- B. 11 sec
- C. 12 sec
- D. 8 sec Discuss
- 8. Two trains of equal length are running on parallel lines in the same direction at 36 km/hr and 26 km/hr. The faster train passes the slower train in 36 sec. The length of each train is ?
Options- A. 28 mts
- B. 54 mts
- C. 24 mts
- D. 50 mts Discuss
- 9. The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 kmph. Then find the speed of faster train ?
Options- A. 68 kmph
- B. 52 kmph
- C. 76 kmph
- D. 50 kmph Discuss
- 10. Two trains are moving in the same direction at 72 kmph and 36 kmph. The faster train crosses a girl sitting at window seat in the slower train in 32 seconds. Find the length of the faster train ?
Options- A. 170 m
- B. 100 m
- C. 270 m
- D. 320 m Discuss
Problems on Trains
Search Results
Correct Answer: 19 kmph
Explanation:
Let the speed of the slower train = p kmph
ATQ,
Speed of the faster train = (p + 6) kmph
Then,
(p + p + 6) x 5 = 160
10p + 30 = 160
10p = 130
p = 13 kmph
Then, speed of the faster train = p + 6 = 13 + 6 = 19 kmph.
Correct Answer: 7.71 sec
Explanation:
Given L1 = 140 m
L2 = 160 m
S1 = 60 km/hr
S2 = 80 km/hr
From the question we get,
S1 + S2 = (L1 + L2) / T
=> (60 + 80) 5/18 m/s = 140 + 160/T
=> T = 54/7 = 7.71 sec
Correct Answer: 6
Explanation:
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
[66*(5/18)] m/sec = (55/3) m/sec
Time taken to pass the man = [110*(3/55)]m/sec = 6 sec.
Correct Answer: 50 kmph
Explanation:
Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec.
[(25/2) x (18/5)] km/hr = 45 km/hr.
Let the speed of the train be 'S' km/hr.
Then, relative speed = (S - 5) km/hr.
S - 5 = 45 => S = 50 km/hr.
Correct Answer: 140 kms
Explanation:
It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, the
Distance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 km
So train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.
Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutes
So distance from A = Distance traveled by 2nd train in 3 hr. 30 min
= 40 x 3.5 = 140 km.
Correct Answer: 444 kms
Explanation:
1h ----- 5 kms
? ------ 60 kms
Time = 12 hrs
Relative Speed = 16 + 21 = 37 kmph
T = 12 hrs
D = S x T = 37 x 12 = 444 kms.
Correct Answer: 10 sec
Explanation:
Relative Speed = 60 -40 = 20 x 5/18 = 100/18
Time = 50
Distance = 50 x 100/18 = 2500/9
Relative Speed = 60 + 40 = 100 x 5/18
Time = 2500/9 x 18/500 = 10 sec.
Correct Answer: 50 mts
Explanation:
Let the length of each train be x mts.
Then, distance covered = 2x mts.
Relative speed = 36 - 26 = 10 km/hr.
= 10 x 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50 mts.
Correct Answer: 68 kmph
Explanation:
Let the speed of the faster train be 'X' kmph,
Then their relative speed= X - 48 kmph
To cross slower train by faster train,
Distance need to be cover = (400 + 600)m = 1 km. and
Time required = 180 sec = 180/3600 hr = 1/20 hr.
Time = Distance/Speed
=> 1/20 = 1/(x-48)
X = 68 kmph
Correct Answer: 320 m
Explanation:
Relative speed = (72 - 36) x 5/18 = 2 x 5 = 10 mps.
Distance covered in 32 sec = 32 x 10 = 320 m.
The length of the faster train = 320 m.
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