(385/1001) = 5/13
First Number is 5
=> Fourth number is 13
Let the numbers be x, x + 2 and X + 4.
Then, x(x + 2)(x +4) / 8 = 720 => x(x + 2)(x +4) = 5760.
?x * ?(x + 2) * ?(x +4) = ?x(x +2)(x + 4 ) = ?5760 = 24?10.
Let the number of girls = x
=> x + x + 4 = 12
=> 2x = 8
=> x = 4
=> Number of girls = 4
=> Number of boys = 4 + 4 = 8
Let the numbers be x and y. Then, 2x + 3y = 39...(i)and 3x + 2y = 30 ...(ii)
On solving (i) and (ii), we get : x = 6 and y = 9.
larger number = 9
Let the two parts be (54 - x) and x.
Then, 10 (54 - x) + 22x = 780
=> 12x = 240
=> x = 20.
Bigger part = (54 - x) = 34.
Let the number be x. Then, 15x - x = 196 <=> 14x = 196 => x = 14..
Let the numbers be x and y. Then,
x^2+y^2=3341......(1)
x^2-y^2=891......(2)
Adding (i) and (ii), we get : 2x^2=4232 or x^2= 2116 or x =46
Subtracting (ii) from (i), we get : 2y^2= 2450 or y^2 = 1225 or y = 35
So, the numbers are 35 and 46
Let the greater and smaller number be p and q respectively.
4q = p + 5 ------ (I)
p = 3q+2 ------- (II)
From equation (I) and (II)
q = 7
p = 23
By hit and trail, we find that
47619 x 7 = 333333.
7) 333333 (47619
333333
----------------
0
And 476190476 x 7 = 3333333333 but smallest number is 47619.
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