Given P = 54 and M = 80
According to the question,
Let ?A? years ago, M = 3P
=> M - A/P - A = 3
=> 80 - A = 3(54 - A)
=> 80 - A = 162 - 3A
=> 2A = 82
=> A = 41
Therefore, A = 41 years ago Sweety?s mother was 3 times of Sweety?s age.
Hence, at the age S = 13 and M = 39.
Age of new boy = (Age of moved girl) ? (Number of family members × Decreased in average)
= 24 ? 24×4/12
= 24 ? 8
= 16 years.
Let the age of Manisha and Sudeshna is 5x and 6x years respectively.
According to the given data,
5x+8/6x+8 = 7/8
42x + 56 = 40x + 64
x = 4
Required Difference of their ages = (6 × 4) ? (5 × 4)
= 4 years.
X= 2/3Y
=> Y= 3/2X
Aage of X after 6 years = 46 years
So present age of X = 46-6 = 40 years
Now, present age of Y = 3/2 * 40 = 60 years.
29 x 2 = 58
20 x 3 = 60
-----------
2 years
Therefore, the age of child is 2 years.
As given Kapil's 8th birthday was celebrated 2 years ago,
Kapil?s present age = 8 + 2 = 10 years.
Father's age is twice of Kapil?s age after 10 years.
=> F + 10 = 2 (K + 10) = 2 (10+ 10)
F = 30years,
Avanthi's age =1/6(F) = 30/6 = 5 years.
Sony and her brother's age sum is 31
Let Sony's mother's age be 'x'.
Now the conditions given for both of their ages related to their mom is
1/5(x-15) + 3/5(x-10) = 31
x-15 + 3x-30 = 155
4x-45 = 155
4x = 200
x = 50
So, Mother's age = 50.
Cross verification : 15 years ago age = 35 => Sony age = 7
10 years ago age = 40 => bro age = 24
Sum = 24 + 7 = 31.
Total ages of 80 boys = 15 x 80 = 1200 yrs.
Total age of 16 boys = 15 x 16 = 240 yrs
Total age of 25 boys = 14 x 25 = 350 yrs.
Average age of remaining boys = 1200 - (240+350) / 80 - (25+15) = 610/41 = 15.25 yrs.
Let their present ages be 13x and 17x.
Then, 13x-4/17x-4 = 11/15.
Solving this, we get x = 2.
Required ratio = 13x2 + 6/17x2 + 6 = 32/40 = 4/5.
By trial and error method from the given options,
as 54 - 45 = (1/11) x (45+54) = 99/11 = 9
Hence this satisfies the given conditions.
Then the woman's husband age is 54.
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