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- Question
In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :
Options- A. 19
- B. 29
- C. 39
- D. 49
- Correct Answer
- 39
ExplanationLet B's present age = x years. Then, A's present age = (x + 9) years.
(x + 9) + 10 = 2(x - 10)=> x + 19 = 2x - 20
=> x =39.
- 1. A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 38 now, the son age 5 years back was :
Options- A. 14
- B. 19
- C. 33
- D. 38 Discuss
- 2. What is the probability that a leap year selected at random, will contain 53 sundays?
Options- A. 1/7
- B. 1/3
- C. 2/7
- D. 4/7 Discuss
- 3. A bag contains 3 black, 4 white and 5 red balls. One ball is drawn at random. Find the probability that it is either black or red ball:
Options- A. 2/3
- B. 1/4
- C. 5/12
- D. 1/2 Discuss
- 4. In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize ?
Options- A. 1/7
- B. 2/7
- C. 3/7
- D. 2/5 Discuss
- 5. Find the probability of selecting 2 woman when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.
Options- A. 1/5
- B. 1/7
- C. 1/6
- D. 1/9 Discuss
- 6. The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?
Options- A. 12
- B. 13
- C. 14
- D. 15 Discuss
- 7. The age of a man is 4 times his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?
Options- A. 24 years
- B. 32 years
- C. 40 years
- D. 44 years Discuss
- 8. The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.
Options- A. 40, 30
- B. 30, 50
- C. 30, 40
- D. 50, 30 Discuss
- 9. The sum of the present ages of a father and his son is 60 years. five years ago, father's age was four times the age of the son. so now the son's age will be:
Options- A. 5
- B. 10
- C. 15
- D. 20 Discuss
- 10. The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new students is?
Options- A. 18 years
- B. 21 years
- C. 19 years
- D. 20 years Discuss
Problems on Ages
Search Results
Correct Answer: 14
Explanation:
Let the son's present age be x years .Then, (38 - x) = x => x= 19.
Son's age 5 years back = (19 - 5) = 14 years
Correct Answer: 2/7
Explanation:
In a leap year,there are 366 days=52 weeks and 2 days
Remaining favourable 2 days can be sunday and monday or saturday and sunday
Exhaustive number of cases =7
Favourable number of cases =2
So,required probability=2/7
Correct Answer: 2/3
Explanation:
P(black ball)=3/12
P(red ball)=5/12
P(black or red)=3/12+5/12=2/3
Correct Answer: 2/7
Explanation:
P(getting prize) = 10/ (10 + 25) =2/7
Correct Answer: 1/6
Explanation:
Out of 9 persons,4 can be choosen in ways =126.
Favourable events for given condition = = 21.
So,required probability = 21/126 =1/6.
Correct Answer: 12
Correct Answer: 32 years
Explanation:
Let the son's be x years, then father's age = 4x years ∴ (4x - 5) = 9(x - 5) ⇒ 5x = 40 ⇒ x = 8 ∴ Present age of the man = 32 years
Correct Answer: 30, 40
Explanation:
As the ratio of their present ages is 3: 4, let their present ages be 3x and 4x. So, 5 years ago, as the ratio of their ages was 5 : 7, =>(3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3x = 30 and 4x = 40
Correct Answer: 15
Explanation:
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 5= 4(x - 5)
55 - x = 4x - 20
5x = 75 => x = 15
Correct Answer: 18 years
Explanation:
Total age of 10 students = 150 years Total age of 15 students = 240 years Total age of 5 new students = 240 - 150 = 90 years Therefore, average age of 5 new students = 90/5 = 18 years
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