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- Question
A bag contains 3 red balls, 5 yellow balls and 7 pink balls. If one ball is drawn at random from the bag, what is the probability that it is either pink or red?
Options- A. 2/3
- B. 1/8
- C. 3/8
- D. 3/4
- Correct Answer
- 2/3
ExplanationGiven number of balls = 3 + 5 + 7 = 15
One ball is drawn randomly = 15C1
probability that it is either pink or red =
- 1. Two cards are drawn from a pack of well shuffled cards. Find the probability that one is a club and other in King
Options- A. 1/52
- B. 1/26
- C. 1/13
- D. 1/2 Discuss
- 2. Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/9. Find the probability that both of them are selected.
Options- A. 1/63
- B. 1/14
- C. 2/63
- D. 1/9 Discuss
- 3. An urn contains 4 white 6 black and 8 red balls . If 3 balls are drawn one by one without replacement, find the probability of getting all white balls.
Options- A. 5/204
- B. 1/204
- C. 13/204
- D. None of these Discuss
- 4. Two letters are randomly chosen from the word TIME. Find the probability that the letters are T and M?
Options- A. 1/4
- B. 1/6
- C. 1/8
- D. 4 Discuss
- 5. A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is:
Options- A. A gain of Rs. 27
- B. A loss of Rs. 37
- C. A loss of Rs. 27
- D. A gain of Rs. 37 Discuss
- 6. When two dice are thrown simultaneously, what is the probability that the sum of the two numbers that turn up is less than 12?
Options- A. 35/36
- B. 17/36
- C. 15/36
- D. 1/36 Discuss
- 7. A coin is tossed 5 times. What is the probability that head appears an odd number of times?
Options- A. 1/2
- B. 1/3
- C. 2/3
- D. 1 Discuss
- 8. A five digit number is formed with the digits 0,1,2,3 and 4 without repetition. Find the chance that the number is divisible by 5.
Options- A. 3/5
- B. 1/5
- C. 2/5
- D. 4/5 Discuss
- 9. What is the probability of an impossible event?
Options- A. 0
- B. -1
- C. 0.1
- D. 1 Discuss
- 10. What is the probability of getting at least one six in a single throw of three unbiased dice?
Options- A. 1/36
- B. 91/256
- C. 13/256
- D. 43/256 Discuss
Probability problems
Search Results
Correct Answer: 1/26
Explanation:
Let X be the event that cards are in a club which is not king and other is the king of club.
Let Y be the event that one is any club card and other is a non-club king.
Hence, required probability:
=P(A)+P(B)
=
= = =
Correct Answer: 2/63
Explanation:
Let A be the event that X is selected and B is the event that Y is selected.
P(A) = 1/7, P(B) = 2/9.
Let C be the event that both are selected.
P(C) = P(A) × P(B) as A and B are independent events:
= (1/7) × (2/9) = 2/63
Correct Answer: 1/204
Explanation:
Let A, B, C be the events of getting a white ball in first, second and third draw respectively, then
Required probability =
=
Now, P(A) = Probability of drawing a white ball in first draw = 4/18 = 2/9
When a white ball is drawn in the first draw there are 17 balls left in the urn, out of which 3 are white
Since the ball drawn is not replaced, therefore after drawing a white ball in the second draw there are 16 balls left in the urn, out of which 2 are white.
Hence the required probability =
Correct Answer: 1/6
Explanation:
Required probability is given by P(E) =
Correct Answer: A loss of Rs. 37
Explanation:
As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order).
The overall resultant will remain same.
So final amount with the person will be (in all cases):
= 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27
Hence the final result is:
64 ? 27 = 37
A loss of Rs.37
Correct Answer: 35/36
Correct Answer: 1/2
Explanation:
The possible outcomes are as follows :
5H, 5T, (H, 4T), (T, 4H), (2H, 3T) (3H, 2T), i.e. 6 outcomes in all.
Therefore the probability that head appears an odd number of times = 3/6 =1/2 (In only three outcomes out of the six outcomes, head appears an odd number of times).
Correct Answer: 1/5
Explanation:
Correct Answer: 0
Explanation:
The probability of an impossible event is 0.
The event is known ahead of time to be not possible, therefore by definition in mathematics, the probability is defined to be 0 which means it can never happen.
The probability of a certain event is 1.
Correct Answer: 91/256
Explanation:
Find the number of cases in which none of the digits show a '6'.
i.e. all three dice show a number other than '6', 5×5×5=125 cases.
Total possible outcomes when three dice are thrown = 216.
The number of outcomes in which at least one die shows a '6' = Total possible outcomes when three dice are thrown - Number of outcomes in which none of them show '6'.
=216?125=91
The required probability = 91/256
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