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There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?

Correct Answer: 3/8

Explanation:

Total cases of checking in the hotels = 4 x 4 x 4 = 64 ways.


Cases when 3 men are checking in different hotels = 4×3×2 = 24 ways.


Required probability =24/64  = 3/8


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