Let A takes x hours, then B = (x+40) hours
1/x + 1/x+40 = 1/15
x = 20
1/K + 1/L + 1/M = 1/8 (Given)
Also given that K = 2L and L = 2M
=> 1/2L + 1/L + 2/L = 1/8
=> (1 + 2 + 4)/2L = 1/8
=> 2L/7 = 8
=> L = 28 hours.
2 pipes open for 2 hours will fill = (2/3) x (2/3) x 3 = 4/3 buckets
Let the slower pipe alone fill the tank in x min.
Then, faster pipe will fill it in x/3 min.
1/x + 3/x = 1/36
Capacity of tank = (8 X 18) = 144 litres
If the capacity of each bucket = 12 litres
Then, Nunber of buckets needed = 144 / 12 = 12 buckets
Then 3/5 th tank fill in =40/3 * 3/5= 8 hours
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