The capacity of a tank is 2400 m3 . A pump can be used both for filling and emptying the tank. The emptying capacity of the pump is 10 m3/minute higher than its filling capacity. And also, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump.

Let filling capacity of the pump be 'F' $m3/\min$

Then, the filling capacity of the pump will be (F + 10) $m3/\min$

From the given data,

$\frac{2400}{F} - \frac{2400}{F+10}= 8\Rightarrow 2400 \frac{F+10-F}{F(F+10)} =8\Rightarrow F2 + 10F - 3000 = 0\Rightarrow F = 50 m3/\min$