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- Question
The capacity of a tank is 2400 m3 . A pump can be used both for filling and emptying the tank. The emptying capacity of the pump is 10 m3/minute higher than its filling capacity. And also, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump.
Options- A. 46 cub.m/min
- B. 44 cub.m/min
- C. 48 cub.m/min
- D. 50 cub.m/min
- Correct Answer
- 50 cub.m/min
ExplanationLet filling capacity of the pump be 'F'
Then, the filling capacity of the pump will be (F + 10)
From the given data,
- 1. Taps X and Y can fill a tank in 30 and 40 minutes respectively.Tap Z can empty the filled tank in 60 minutes.If all the three taps are kept open for one minute each,how much time will the taps take to fill the tank?
Options- A. 48min
- B. 72min
- C. 24min
- D. None of these Discuss
- 2. Pipe A is an inlet pipe that can fill an empty cistern in 69 hours. Pipe B can drain the filled cistern in 46hours. When the cistern was filled the two pipes are opened one at a time for an hour each, starting withPipe B. how long will it take for the cistern to be empty?
Options- A. 11 days 10 hours
- B. 11 days 7 hours
- C. 11 days 12 hours
- D. 1 days 13 hours Discuss
- 3. A large tanker can be filled by two pipes A and B in 60 and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half ?
Options- A. 31 min
- B. 29 min
- C. 28 min
- D. 30 min Discuss
- 4. Two pipes A and B can fill a tank in 16 hrs and 12 hrs respectively. The capacity of the tank is 240 liters. Both the pipes are opened simultaneously and closed after 2 hrs. How much more water need to fill the tank?
Options- A. 70 lit
- B. 170 lit
- C. 90 lit
- D. 190 lit Discuss
- 5. One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 min, then the slower alone will be able to fill the tank in:
Options- A. 81 min
- B. 108 min
- C. 144 min
- D. 192 min Discuss
- 6. Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes ?
Options- A. 21 min
- B. 24 min
- C. 20 min
- D. 22 min Discuss
- 7. The ratio of efficiencies of two filling pipes is 4 : 5. There is a third emptying pipe which efficiency is two third of the average efficiency of first two filling pipes can empty a filled tank in 36 minutes. In how much time both the filling pipes can fill the tank when it is empty?
Options- A. 16 min
- B. 12 min
- C. 14 min
- D. 20 min Discuss
- 8. A tap can fill a tank in 6 hours. After half the tank is filled three more similar taps are opened. What is the total time taken to fill the tank completely ?
Options- A. 4 hrs 15 min
- B. 3 hrs 24 min
- C. 4 hrs 51 min
- D. 3 hrs 45 min Discuss
- 9. One fill pipe A is 3 times faster than second fill pipe B and takes 32 minutes less than the fill pipe B. When will the cistern be full if both pipes are opened together?
Options- A. 6 min
- B. 8 min
- C. 12 min
- D. 10 min Discuss
- 10. A water tank in a village is normally filled in 8 hours but takes 2 hours longer to fill because of a leak in its bottom. If the tank is full, in how many hrs will the leak empty it ?
Options- A. 34 hrs
- B. 36 hrs
- C. 38 hrs
- D. 40 hrs Discuss
Pipes and Cistern problems
Search Results
Correct Answer: 24min
Explanation:
Given taps X and Y can fill the tank in 30 and 40 minutes respectively. Therefore,
part filled by tap X in 1 minute = 1/30
part filled by tap Y in 1 minute = 1/40
Tap Z can empty the tank in 60 minutes. Therefore,
part emptied by tap Z in 1 minute = 1/60
Net part filled by Pipes X,Y,Z together in 1 minute = [1/30 +1/40 - 1/60] = 5/120 = 1/24
i.e., the tank can be filled in 24 minutes.
Correct Answer: 11 days 7 hours
Correct Answer: 30 min
Explanation:
Part filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
(x/2) * (1/15) = 1 => x = 30 min.
Correct Answer: 170 lit
Explanation:
Given A alone can fill the tank of capacity 240 lit in 16 hrs.
=> A can fill in 1 hr = 240/16 = 15 lit
=> B alone can fill the tank of capacity 240 lit in 12 hrs.
=> B can fill in 1 hr = 240/12 = 20 lit
Now, (A + B) in 1 hr = 15 + 20 = 35 lit
But they are opened for 2 hrs
=> 2 x 35 = 70 lit rae filled
Remaining water to be filled in tank of 240 lit = 240 - 70 = 170 lit.
Correct Answer: 144 min
Explanation:
Let the slower pipe alone fill the tank in x minutes.
Then,faster pipe will fill it in x/3 minutes.
Correct Answer: 21 min
Explanation:
Let the pipe B be closed after 'K' minutes.
30/16 - K/24 = 1 => K/24 = 30/16 - 1 = 14/16
=> K = 14/16 x 24 = 21 min.
Correct Answer: 12 min
Explanation:
Let the efficiencies of filling pipes is 4p and 5p respectively.
Efficiency of pipe which empty the tank = 2/3 x 9p/2 = 3p
Total work = 3p x 36 = 108p
Time to fill the tank by both the pipes = 108p/9p = 12 min.
Correct Answer: 3 hrs 45 min
Explanation:
Time taken by one tap to fill half of the tank = 3 hrs.
Part filled by the taps in 1 hour = 4 x 1/6 = 2/3
Remaining part = 1 - 1/2 = 1/2
2/3 : 1/2 :: 1 : p
p = 1/2 x 1 x 3/2 = 3/4 hrs. i.e., 45 min
So, total time taken = 3 hrs 45 min.
Correct Answer: 12 min
Explanation:
Let pipe A takes p min to fill
Then,
pipe B takes 3p min to fill
=> 3p - p = 32
=> p = 16 min => 3p = 48 min
Required, both pipes to fill = (48 x 16)/(48 + 16) min = 12 min.
Correct Answer: 40 hrs
Explanation:
The time taken by the leak to empty the tank =
Therefore, the leak empties the tank in 40 hours.
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