We get this using the formula of circular permutations i.e., (4 - 1)! = 3! =6
Let us assume the number of boys = B and number of girls = G.
According to question,
B + G = 30
Lets us assume total weight of boys = W1 and total weight of girls = W2
average weight of boys = total weight of boys/number of boys
total weight of boys/number of boys = 20
W1/B = 20
W1 = 20B
average weight of girls = total weight of girls/number of girls
25 = W2/G
W2 = 25G
Data is not sufficient to solve the equation.
since we do not know either the average weight of the whole class or the ratio of no. of boys to girls.
Given, a = 12, b =16 , c =18, k = 5
According to the formula,
Required number =(LCM of a, b and c) + k
= (LCM Of 12, 16, 18) + 5
LCM of 12, 16, 18 is
? LCM = 2 x 2 x 3 x 4 x 3 = 144
? Required number =144 + 5 = 149
Let R's capital = 1
Then, Q's capital = 4
2 (P's capital) = 3 (Q's capital) = 3 x 4 = 12
? P's capital = 12/2 = 6
? P's share : Q's share : R's share = 6 : 4 : 1
Thus, Q's share profit = { 4/(6 + 4 + 1)} x 148500
= (4/11) x 148500
= 4 x 13500
= ? 54000
Let numbers are 2N and 3N.
According to the question, 6N = 48
? N = 8 ( ? LCM = 6N )
? Required sum = ( 2N + 3N ) = 5N
= 5 x 8 = 40
Given Ratio = 7/2 : 4/3 : 6/5 = 105 : 40 : 36
Let them initially invest Rs. 105, Rs. 40 and Rs. 36 respectively.
Ratio investment = [105 x 4 + (150% of 105) x 8] : (40 x 12) : (36 x 12)
=1680 : 480 : 432 = 35 : 10 : 9
? B's share = Rs. 21600 x (10/54) = Rs. 4000
LCM of 11 and 13 will be (11 x 13). Hence, if a number is exactly divisible by 11 x 13, then the same number must be exactly divisible by their LCM or by (11 x 13).
Let numbers are 5N and 6N.
Now, HCF of these two numbers is N.
We know that,
LCM x HCF = Product of two numbers
? 480 x N = 5N x 6N
? 480N = 30N2
? N =16
A's 1 day's work = (1/15 - 1/20) = 1/60
? A alone can finish it in 60 days.
We have, m x n = 6 x 210 = 1260
? 1/m + 1/n = (m + n)/mn = 72/1260 = 4/70 = 2/35
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