Sum = (B.D. x T.D.) / (B.D. - T.D.) = Rs. (36 x 30) / 6
= Rs. 180
Required H.C.F. = | H.C.F. of 9, 12, 18, 21 | = | 3 |
L.C.M. of 10, 25, 35, 40 | 1400 |
7 spiders make 7 webs in 7 days.
? 1 spiders make 7 webs in 7 x 7 days.
? 1 spiders make 1 webs in 7 x 7 / 7 days.
? 1 spiders make 1 webs in 7 days.
134% of 3894 + 38.94% of 134 = ?
? ? = (3894 x 134)/100 + (38.94 x 134)/100
= 5217.96 + 52.1796
= 5270.1396 ? 5270
2 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)]
= 2 x [(36 x 48 x 250) / (12 x 9 x 5)]
= 2 x 4 x 4 x 50 = 1600
Let us assume Ram has R rupees and Mohan has M rupees.
According to question,
If Ram gives 30 rupees to Mohan, then
Ram has left money = R - 30 and Mohan has money = M + 30
Then Mohan will have twice the money left with Ram,
M + 30 = 2(R - 30)
M + 30 = 2R - 60
2R - M = 90................................(1)
Again According to question,
if Mohan gives 10 rupees to Ram, then
Mohan has left the money = M - 10 and Ram has the money = R + 10
Then According to question,
Ram will have thrice as much as is left with Mohan,
R + 10 = 3 (M - 10 )
? R + 10 = 3M - 30
? 3M - R = 10 + 30
? 3M - R = 40..................................(2)
After Multiplying 2 with Equation (2) , add with the equation (1),
6M - 2R + 2R - M = 80 + 90
? 6M - M = 170
? 5M = 170
? M = 170/5
? M = 34
Put the value of M in equation (1), we will get
? 2R - 34 = 90
? 2R = 90 + 34
? 2R = 124
? R = 124/2
? R = 62
Let total distance = x km
According to the question,
x/3 - x/4 = 1/2;
? x/12 = 1/2
? x = 6 km
Let the positive number be N.
According to the question,
N + 10 = 200/N
? N2 + 10N = 200
? N2 + 10N - 200 = 0
? ( N - 10) ( N + 20) = 0
&ythere4; N = 10 and N = -20
But N ? -20, since N is a positive number.
So, the required number is 10.
(b) log (2 + 3) = log 5 and log (2 x 3) = log 6 = log 2 + log 3
∴ log (2 + 3) ≠ log (2 x 3)
(c) Since loga 1 = 0, so log10 1 = 0.
(d) log (1 + 2 + 3) = log 6 = log (1 x 2 x 3) = log 1 + log 2 + log 3.
So, (b) is incorrect.
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