As per figure we can calculate the ration as below
Number of officers / Number of workers = 1000 / 7000 = 1 / 7
No. of officers = 1 / (1 + 7) × 400 = 50
No. of workers = 400 ? 50 = 350
Volume of the Earth taken out = 30 x 20 x 12
= 7200 m3
Area of the remaining portion (leaving the area of dug out portion) = 470 x 30 + 30 x 10
= 14100 + 300 = 14400 m3
Let h be height to which the field is raised by spreading the Earth dug out.
Then, 14400 x h = 7200
? h = 7200/14400 = 0.5 m
Here, p1 : p2 : p3 = 5 : 3 : 1 and x1 : x2 : x3 = 5 : 6 : 8
According to the formula,
Required ratio = p1/x1 : p2/x2 : p3/x3
= 5/5 : 3/6 : 1/8
= 1 : 1/2 : 1/8 = 8 : 8/2 : 8/8 = 8 : 4 : 1
Total profit - Remuneration = Balance profit This balance profit is divided in proportion to their investment
? (Balance Profit of A) / (Balance Profit of B) = (Investment of A) / (investment of B)
? (390 - 10 x 12) / balance of Profit of B = 3000/4000 = 3/4
(Since remuneration of A is Rs. 10 per month)
? Balance profit of B = (4 x 270)/3 = Rs. 360
Since B does not get any remuneration, hence B receives Rs. 360 at the end of the year.
Let the number of correct answer be x and number of wrong answer be y.
Then, 4x - y = 200 ..(i)
and x + y = 200 ..(ii)
On adding Eqs. (i) and (ii), we get
4x - y = 200
x + y = 200
----------------
5x = 400
? x = 80
Let us assume the first number is x and second number is y.
According to question,
sum of twice the first number and thrice the second number is 100.
2x + 3y = 100 ...................(1)
and sum of thrice the first number and twice the second number is 120.
3x + 2y = 120...................(2)
Subtract equation (1) from Equation (2) after multiply 2 with Equation (1) and 3 with Equation (2), we will get.
3(3x + 2y) - 2(2x + 3y) = 3 x 120 - 2 x 100
9x + 6y - 4x - 6y = 360 - 200
5x = 160
x = 32
put the value of x in equation (1)
2 x 32 +3y = 100
3y = 100 - 64
3y = 36
y = 12
The larger Number is 32 .
Let C's capital = Rs.N Then B's capital = Rs. 4N
? 2(A's capital) = 3 (B's capital) = 12N
? A's capital = 6N
? A : B : C = 6N : 4N : N = 6 : 4 : 1
? C's share = Rs. 5940 x (1/11) = Rs. 540
Given, 2a + 3b = 17
and 2a + 2 - 3b + 1 = 5
? 22 x 22 - 3b x 31 = 5
? 4.2a - 3.3b = 5
Let 2a = x amd 3b = y
Then, x + y = 17 ...(i)
4x - 3y = 5 ...(ii)
On multiplying Eq. (i) by 3 and adding to Eq (ii), we get
3x + 3y = 51
4x - 3y = 5
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7x = 56
? x = 8
On putting the value of x in Eq. (i), we get
8 + y = 17
? y = 9
Now, 2a = x
? 2a = 8 (2)3
? 3b = y = 9
? 3b = 32
? b = 2
Hence, a = 3 and b = 2
The minute hand to coincide with the hour hand it should trace at first 5 minute spaces and then the hands of the clocks to be opposite to each other minute hand should trace 30 minute spaces i.e. totally it should gain 5 + 30 = 35 minute spaces to be opposite to that of hour hand.
We know that, Minute hand gains 55 minute spaces over hour hand in 1 hour. Therefore, Minute hand gain 40 minute spaces over hand in 35 x (60/55) = 38(2/11).
Hence the hand of the clock will minutes be opposite to each at 38 (2/11) past 1'O clock. Therefore, Correct option is B.
Milk = (729 x 7/9) = 567 ml
Water = (729 x 2/9) = 162 ml
Let water to be added is w
? 567 / (162 + w) = 7/3
? 3 x 567 - 7 x 162 = 7 x w
? 1701 - 1134 = 7 x w
? 7w = 1701 - 1134
? w = 567/7 = 81 ml
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