Let the total population be 'P'
P x (96/100) = 23040
P = 240 * 100
P = 24000.
Here, k = 7 and l = 28
Therefore, first number =
x100 % of second number = 7/28 x 100% of second number = 25% of second number.
Let X be the total amount with Ramesh
Given 28% of X = Cash remaining
=> Amount spent = 72% of X = 38460 + 24468 = 62928
=> 72% of X = 62928
=> X = ?
=> X = 87400
16 of 225 is =
Given that to find 15 of 80
=> What % of 80 is 15
Let it be 'p'
=> p% of 80 = 15
=>
Therefore, 15 is 18.75% of 80 => 18.75% of 80 = 15
Example::
Now, in the similar way we can find 15% of 80 =?
=> 15x80/100 = p
=> p = 4 x 3 = 12
Therefore, 15% of 80 = 12
Given,
25% of three-seventh of 26% of a number is 145.5
Let the required number be 'N'
i.e,
N =
=> N = 5223.07
Let the required number be 'p'
36 of what number is 18 implies 36% of p = 18
=> 36 x p/100 = 18
=> p = 1800/36
=> p = 50.
Hence, 36% of 50 is 18.
From the given data,
let the amounts invested be 4p, 5p and 3p
Net profit = Total profit - Total loss
= 10x5p/100 + 25x3p/200 - 20x4p/100
= 0.875p - 0.8p
= 0.075p
Therefore, profit% = (Net profit/Total investment) x 100
= 0.075 x 100/12
= 0.0625%
Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,
As we know:
Simple interest (S.I.) = PTR/100
(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200
= 10a + 12b + 15c = 320000 .........(1)
Now, c = 240% of b = 12b/5 .........(2)
And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)
From (1), (2) and (3), we have
16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000
? Sum invested in Scheme Y = Rs.5000.
74.99% of 1299 + 8.98% of 1899 = ?
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