Given the angles of a quadrilateral are in the ratio of 2:4:7:5
Let the angles of a quadrilateral are 2x, 4x, 7x, 5x
But we know that sum of the angles = 360 degrees.
=> 2x + 4x + 7x + 5x = 360
=> x = 20
Therfore, the smallest angle of the quadrilateral = 2x = 2x20 = 40 degrees.
One of the angle of the triangle = 2 x 40 = 80 degrees
The other angle is 180 - (40 + 80) = 60 degrees.
Hence the second largest angle of the triangle is 60 degrees.
Let the diagonals of the squares be 2x and 5x respectively.
Ratio of their areas =
Given numbers are 1.08 , 0.36 and 0.90
H.C.F of 108, 36 and 90 is 18 [ G.C.D is nothing but H.C.F]
Therefore, H.C.F of given numbers = 0.18
We know the rule that,
At particular time for all object , ratio of height and shadow are same.
Let the height of the pole be 'H'
Then
=> H = 108 m.
area of a square = a² sq cm
length of the diagonal = cm
area of equilateral triangle with side
=
required ratio =
Required Number = (L.C.M of 12, 16, 18,21,28)+7
= 1008 + 7
= 1015
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