To find the LCM of 24, 36 and 40
24 = 2 x 2 x 2 x 3
36 = 2 x 2 x 3 x 3
40 = 2 x 2 x 2 x 5
Now, LCM of 24, 36 and 40 = 2 x 2 x 2 x 3 x 3 x 5
= 8 x 9 x 5
= 72 x 5
= 360
Let us calculate both the length and width of the room in centimeters.
Length = 6 meters and 24 centimeters = 624 cm
width = 4 meters and 32 centimeters = 432 cm
As we want the least number of square tiles required, it means the length of each square tile should be as large as possible.Further,the length of each square tile should be a factor of both the length and width of the room.
Hence, the length of each square tile will be equal to the HCF of the length and width of the room = HCF of 624 and 432 = 48
Thus, the number of square tiles required = (624 x 432 ) / (48 x 48) = 13 x 9 = 117
4 x 27 x 3125 = ;
8 x 9 x 25 x 7 =
16 x 81 x 5 x 11 x 49 =
H.C.F = = 180.
Let the numbers be x and 4x. Then,
Hence Larger Number = 4x = 84
If we want to pack the drinks in the least number of cans possible, then each can should contain the maximum numbers of liters possible.As each can contains the same number liters of a drink, the number of liters in each can is a comman factor for 80,144 and 368; and it is also the highest such factor, as we need to store the maximum number of liters in each can.
So, the number of liters in each can = HCF of 80,144 and 368 = 16 liters.
Now, number of cans of Maaza = 80/16 = 5
Number of cans of Pepsi = 144/16 = 9
Number of cans of Sprite = 368/16 = 23
Thus, the total number of cans required = 5 + 9 + 23 = 37
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds(2 minutes).
In 30 minutes,they will together (30/2)+1=16 times
To know the the measuring cylinder that can fill all the given capacities , they must be divisible by the required number.
98,182,266 all are divisible by 14
So 14 litres is the largest cylinder that can fill all the given cylinders.
(or)
The other method is take HCF of all given capacities i.e 98, 182 and 266.
Given numbers are 1, 2 and 3
Factors of 1 = 1
Factors of 2 = 1, 2
Factors of 3 = 1, 2 and 3
Common factors = 1
Hence, the HCF of 1, 2 and 3 = 1.
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
G.C.D is nothing but H.C.F
Given numbers are 1.08 , 0.36 and 0.90
we can take as 108, 36 and 90
Then required H.C.F is 18.
Therefore, H.C.F of given numbers is 0.18.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.