We know Compound Interest = C.I. = P1+r100t - 1
Here P = 2680, r = 8 and t = 2
C.I. = 26801 + 81002-1= 268027252-12= 26802725+12725-1= 2680 5225×225
= (2680 x 52 x 2)/625
= 445.95
Compound Interest = Rs. 445.95
S.I=PNR/100
C.I. when interest
compounded yearly=rs.[5000*(1+4/100)(1+1/2*4/100)]
= Rs. 5304.
C.I. when interest is
compounded half-yearly=rs.5000(1+2/100)^3
= Rs. 5306.04
Difference = Rs. (5306.04 - 5304) = Rs. 2.04
S.I. on Rs.800 for 1 year
=Rs[840 - 800]
= Rs.40
Rate
=(100x40/800x1)%
= 5%
Let us assume Amount be 100 Rs and we calculate in CI
First year 60% of 100 = 60 amount (100+60) is 160
Second year 60% of 160 = 96 amount (160+96) is 256
Third year 60% of 256 =153.6 amount (256+153.6) is 409.6
Here the Amount of 100 Rs is quadrapled in 3 years.
One year contains 2 half years
Three year has 6 half years.
Therefore, It takes 6 half years.
Total amount for two years =
Now , interest for third year =
Let the sum be Rs. P
P{
- 1 } = 2828.80
It is in the form of
P(8/100)(2 + 8/100) = 2828.80
P = 2828.80 / (0.08)(2.08)
= 1360/0.08 = 17000
Principal + Interest = Rs. 19828.80
Given principal amount = Rs. 8000
Time = 3yrs
Rate = 5%
C.I for 3 yrs =
Now, C.I for 2 yrs =
Hence, the required difference in C.I is 1261 - 820 = Rs. 441
so, answer is 4 years
Let the sum be Rs. x. Then,
Thus, the sum is Rs. 2160
We know that,
From given data, P = Rs. 8625
Now, C.I =
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