Let 'R%' be the rate of interest
From the given data,
Hence, the rate of interest R = 5% per annum.
We know the formula for calculating
The compound interest where P = amount, r = rate of interest, n = time
Here P = 5000, r1 = 10, r2 = 20
Then
C = Rs. 4826.
C.I.= Rs.[4000*(1+10/100)^2-4000]
=Rs.840
sum=Rs.(420 * 100)/3*8=Rs.1750
Present Worth
=
=
= Rs.156.25
Interest earned in scheme M =
Interest earned in scheme N =
Now, from the given data,
k = 11
Let Rs. K invested in each scheme
Two years C.I on 20% = 20 + 20 + 20x20/100 = 44%
Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25%
Now,
(P x 44/100) - (P x 32.25/100) = 528.75
=> 11.75 P = 52875
=> P = Rs. 4500
Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.
8000 × 33.1% = 2648
Compound Interest for 1 1?2 years when interest is compounded yearly = Rs.(5304 - 5000)
Amount after 11?2 years when interest is compounded half-yearly
Compound Interest for 1 1?2 years when interest is compounded half-yearly = Rs.(5306.04 - 5000)
Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04
Given compound interest for 3 years = Rs. 1513.2
and simple interest for 5 years = Rs. 2400
Now, we know that C.I =
=> 1513.2 = ...........(A)
And S.I = PTR/100
=> 2400 = P5R/100 ..................(B)
By solving (A) & (B), we get
R = 5%.
Amount
= Rs.(25000x(1+12/100)³
= Rs.(25000x28/25x28/25x28/25)
= Rs. 35123.20.
C.I = Rs(35123.20 -25000)
= Rs.10123.20
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