At 3 O'clock, Minute hand is at 12 while the Hour hand is at 3. Again the minute hand has to sweep through ( 30 x 5 ) ie 150° for reaching the figure 5 to show 25 mins.
Simultaneously the Hour hand will also rotate for 25 mins. Thus starting from the mark, 3 the hour hand will cover an angle = (25 x 30) / 60 = 12.5°
Hence, Angle between Hour and the Minute hand = ( 60 - 12.5 ) = 47.5°
Let sale in 2008 = 100
Sale in 2009 = 20
Sale in 2010 = 100
? Required increases = [(100 - 20)/20] x100
= (80/20) x 100 = 400%
Last year number of boys in school = 610
? Number of boys in school this year = 610 - (610 x 20)/100
= 610 - 122 = 488
? Number of girls in school this year
= Number of boys in school this year x 175%
= (488 x 175)/100
= (488 x 7)/4
= 122 x 7
= 854
Hence, number of girls in school this year in 854.
Mr. Sen's monthly income
= (Bina + Anita)'s monthly income = 775200/12 = ? 64600
According to the question.
Bina's monthly income = 90% of Anita's monthly income
? Bina/Anita = 90/100 = 9 /10
? Bina : Anita = 9 : 10
? Bina's Monthly salary
= (9/19) x 64600
= ? 30600
? J = 40% of A =2A/5
? P = 1/4 x 2A/5 = A/10
? A/10 - 200 = 600
? A/10 = 800
? A = Rs. 8000
Let the number of students appearing for examination in the year 1998 in the states A, B and C be 3N, 5N,and 6N respectively.
According to the question, {(3N x 120)/100} / {(6N x 110)/100} = 1/2
Its true for every N so, The data is inadequate.
? 36% of N = (113 + 85)
? N = (100 x 198) / 36 = 550
Reduction in consumption = { m / (100 + m)} x 100%
= (25/125) x 100%
= 20%
Let the number of boys = x
then x + 7x/10 = 85
? x = 50
? No. of girls = 85 - 50 = 35
(i) Number of boys playing only badminton =50% of boys
= 50/100 x 50 = 25
(ii) Number of children playing only table tennis
= 40% of total no. of children
= 40/100 x 85 = 34
(iii) Total no. of children playing both badminton and table tennis = 12
Hence, number of girls playing only badminton = 85 - (25 + 34 + 12)
= 85 - 71 = 14.
40% = 24 questions.
? Total question = (100/40) x 24 = 60
Suppose N% familes own both a car and a phone, then
percentage of the families owing only a phone = 25 - N
Percentage of the families owing only a car = 15 - N
? (25 - N) +(15 - N) + N + 65 = 100
? N = 5
Percentage of families who have either a car or a phone = (25 - 5) + (15 - 5) + 5 = 35
So, Statement ll is correct.
Now, suppose the total number of families in the town be A.
? (5 x A)/100 = 2000 ? A = 40000
So, Statement lll is also correct.
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