Let the Required cost be X paise. Less Weight , Less cost (Direct Proportion)
Therefore, 250 : 200 :: 60 : x
=> (250 * x) = (200 * 60)
=> x= 48
Cost of x metres = Rs. d.
Cost of 1 metre = Rs.(d/x)
Cost of y metres = Rs.[(d/x).y] = Rs.(yd/x)
After 10 days : 150 men had food for 35 days.
Suppose 125 men had food for x days.
Now, Less men, More days (Indirect Proportion)
125 : 150 :: 35 : x 125 x x = 150 x 35
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
14 : 6 :: 21 : x => 14 x x = 6 x 21
x=6*21/14 => x=9
Let the required no of hectares be x. Then
More men, More hectares (Direct proportion)
More days, More hectares (Direct proportion)
=> ( 8 * 24 * x) = (36 * 30 * 80)
=> x= 450
Assume first child (the youngest) get = Rs. x
According to the question ;
each son having Rs. 30 more than the younger one
Second child will get = Rs. x + 30
Third child will get = Rs. x + 30 + 30 = x + 60
Forth child will get = Rs. x + 30 + 30 + 30 = x + 90
Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120
Total amount they got = Rs. 2000
x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Rs. 340
So the youngest child will get Rs. 340.
Let the required number of days be x.
Less cows, More days (Indirect Proportion)
Less bags, Less days (Direct Proportion)
1 x 40 x x = 40 x 1 x 40
=> x = 40.
Let the required number of bottles be x.
More weavers, More mats (Direct Proportion)
More days, More mats (Direct Proportion)
4 x 4 x x = 8 x 8 x 4
=> x =
=> x = 16.
There is a meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children = 120 men.
50 children = =30men
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
=> 15 * 12 * x = 10 * 18 * 6
=>x = 6
(Men 14 : 16) : (Hrs/Day 12 : 7) :: 48 : x
14 * 12 * x = 16 * 7 * 48 or x = 32
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