Here from 4th December 1999 to 3rd January 2000,
there is a difference of 30 days.
Number of odd days = 30/7 = 2 odd days
Then no. of odd days = 2 => tuesday and wednesday(from monday).
Hence on 3rd january it is wednesday.
18 Feb, 2016 = (2015 years + Period from 1.1.2016 to 18.2.2016)
Odd days in 1600 years = 0
Odd days in 400 years = 0
15 years = (12 ordinary years + 3 leap year) = (12 x 1 + 3 x 2)= 4 odd days
Jan Feb
(31 + 18 ) = 49 days
49 days = (7 weeks + 0 day)= 0 odd day.
Total number of odd days = (0 + 0 + 4 + 0) = 4 odd day.
Given day is Thursday
Given year 1939, when divided by 4 leaves a remainder of 3.
NOTE: When remainder is 3, 11 is added to the given year to get the result.
So, 1939 + 11 = 1950
The year 1985 is an ordinary year. So, it has 1 odd day.
So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.
But, 19th June,1984 is Monday
S0, 19th June, 1985 is Tuesday.
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days => 0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Given year 1856, when divided by 4 leaves a remainder of 0.
NOTE: When remainder is 0, 28 is added to the given year to get the result.
So, 1856 + 28 = 1884
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