Given that 2.12.91 is the first Tuesday
Hence we can assume that 4.12.91 is the first Thursday
If we add 7 days to 4.12.91, we will get second Thursday
If we add 14 days to 4.12.91, we will get third Thursday
If we add 21 days to 4.12.91, we will get fourth Thursday
=> fourth Thursday = (4.12.91 + 21 days) = 25.12.91.
We know that when m is a odd number ( xm + am ) is divisible by ( x + a ).
? Each one is divisible by (41 + 43).
So Common factor = (41 + 43).
Certain sum for the person = (900 x 100)/(6 x 3) =Rs. 5000
? Interest on Rs. 5000 by C.I. = 5000(1 +6/100)3 - 5000 = Rs. 955.08
? More interest =Rs. (955.08 - 900) = Rs. 55.08
We know that , ?6 = 2.44, ?5 = 2.23, ?3 = 1.73
a = ?6 - ?5 = 2.44 - 2.23 = 0.21
b = ?5 - 2 = 2.23 - 2 = 0.23
c = 2 - ?3 = 2 - 1.73 = 0.27
Let the CP be Rs. x , then SP be 0.96x
? 0.96x = 240
? x = 250
Now the new SP = 250 X 1.1 = 275
Given expression 280.5 / 25.5 = 2805 / 255
= 2805 / (2.55 x 100)
= 1100 / 100
=11
Let age of Purvi = N yr
Then, age of Anil = 1.5N yr
According to the question,
(1.5N + 8)/(N + 8) = 25/18
? 27N + 144 = 25N + 200
? N = 56/2 = 28
Hence, present age of Purvi = 28 yr
Rs. 794.50 = 112.5 + (1/100) x Amount of stock
? Amount of stock = (794.50 x 100) / 113.5 = Rs. 700
Let us assume the salary of driver be ? R
Then Tips of week = R x 5/4
According to question,
his income during one week = Salary + Tips
? Total Income during one week = R + (5R/4)
? Total Income during one week = (4R + 5R)/4 = 9R/4
Required Fraction = Tips in a week/Total Income in a week
? Required Fraction = 5R/4 / 9R/4
? Required Fraction = 5R/4 x 4/9R
? Required Fraction = 5/9
Let required amount of coal be y metric tonnes
9 engines consumes 24 metric tonnes of coal in 8 hours a day.
More engines, more amount of coal (direct proportion)
If 3 engines of first type consume 1 unit, then 1 engine will consume 1/3 unit which is its the rate of consumption.
If 4 engines of second type consume 1 unit, then 1 engine will consume 1/4 unit which is its the rate of consumption
More rate of consumption, more amount of coal (direct proportion)
More hours, more amount of coal(direct proportion)
Now we have , 9 × ( 1 / 3 ) × 8 × y = 8 × ( 1 / 4 ) × 13 × 24
? 3 × 8 × y = 8 × 6 × 13
? 3 × y = 6 × 13 ? y = 2 x 13 = 26 metric tonnes
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