Sum of the remaining two numbers = (3.95 * 6) - [(3.4 * 2) + (3.85 * 2)]
= 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20.
Required average = (9.2 / 2) = 4.6.
Total money decided to contribute = 750 x 12 = 9000
Let 'b' boys dropped
The rest paid 150/- more
=> (12 - b) x 900 = 9000
=> b = 2
Hence, the number of boys who dropped out is 2.
We have : ( a + b + c) / 3 = M or (a + b + c) = 3M.
Now. .
Required mean = .
Using Trial and error method,
we get the number of girls in the hall = 78
Let average expenditure was Rs. R
13 x 79 + 6x(R + 4) = 19R
=> R = Rs. 80.84
Total money = 19 x 80.84 = Rs. 1536.07.
Given total number of passengers in the bus = 45
First average weight of 45 passengers = 52 kgs
Average weight of 5 passengers who leave bus = 48
Average weight of 5 passengers who joined the bus = 54
Therefore, the net average weight of the bus is given by
Total employees =
Hence number of educated employees = 30-20 = 10
Let the number of boys = b
Let the number of girls = g
From the given data,
81b + 83g = 81.8(b + g)
81.8b - 81b = 83g - 81.8g
0.8b = 1.2g
b/g = 1.2/0.8 = 12/8 = 3/2
=> g : b = 2 : 3
Hence, ratio between the number of girls to the number of boys = 2 : 3.
The total marks of all 5 subjects = 82 x 5 = 410
Total marks of 1st two subjects = 86.5 x 2 = 173
Total marks of last two subjects = 84 x 2 = 168
Now, marks in 3rd subject = 410 - (173 + 168) = 410 - 341 = 69.
16x + 85 = 17(x + 3)
x = 34 + 3 = 37
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