The length of a rectangle is 10 cm more than the breadth. Find the diagonal length of rectangle if perimeter is 44 cm ?

Let the length of the rectangle = L cm

Then the breadth of the rectangle = (L - 10) cm

Perimeter of a rectangle = 2(L + B) cm

=> 44 = 2(L + L - 10)

=> 44 = 4L - 20

=> 4L = 64

=> L = 16 cm

=> B = L - 10 = 6 cm

Diagonal =  $L2+B2$ =  $162+62$ = 17.08 cm