The amount of petrol left after 4 operations
=
=
=
= 81.92 litres
Hence the amount of kerosene = 200 - 81.92 = 118. 08 litres
A certain industrial loom weaves 0.128 meters of cloth in 1 second.
A certain industrial loom weaves 1 meters of cloth in 1/0.128 second.
A certain industrial loom weaves 25 meters of cloth in 25 x 1/ 0.128 second.
A certain industrial loom weaves 25 meters of cloth in 195.312 second.
15 Cows eat as much as 21 Goats.
? 1 Cows eat as much as 21/ 15 Goats.
? 35 Cows eat as much as 21 x 35 / 15 Goats.
? 35 Cows eat as much as 21 x 7 / 3 Goats.
? 35 Cows eat as much as 7 x 7 Goats.
? 35 Cows eat as much as 49 Goats.
40 cows eat 40 bags of husk in 40 days.
? 1 cows eat 40 bags of husk in 40 x 40 days.
? 1 cows eat 1 bags of husk in 40 x 40 / 40 days.
? 1 cows eat 1 bags of husk in 40 days.
According to the question,
Every day adding 1 rs extra to previous day.
Let us assume after n day, total saving will become perfect square.
1 + 2 + 3 + 4 + 5 + 6 +.......................+ tn.
Apply the algebra A.P formula,
sum of total rupees after n days = n(n+1)/2
Hit and trail method, Put the value of n = 2 , 3 , 4, 5 .... and so on to get the perfect square.
If n = 2
n(n+1)/2 = 2 x 3 / 2 = 3 which is not perfect Square.
If n = 3
n(n+1)/2 = 3 x 4 / 2 = 6 which is not perfect Square.
If n = 4
n(n+1)/2 = 4 x 5 / 2 = 10 which is not perfect Square.
If n = 5
n(n+1)/2 = 5 x 6 / 2 = 15 which is not perfect Square.
If n = 6
n(n+1)/2 = 6 x 7 / 2 = 21 which is not perfect Square.
If n = 7
n(n+1)/2 = 7 x 8 / 2 = 28 which is not perfect Square.
If n = 8
n(n+1)/2 = 8 x 9 / 2 = 36 which is perfect Square.
n(n+1)/2 should be a perfect square . The first value of n when this occurs would be for n = 8. thus , on the 8th of March of the required condition would come true.
So, their average price = Rs. | ❨ | 126 + 135 | ❩ | = Rs. 130.50 |
2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
Rs. 130.50 | Mean Price Rs. 153 |
Rs. x |
(x - 153) | 22.50 |
∴ | x - 153 | = 1 |
22.50 |
⟹ x - 153 = 22.50
⟹ x = 175.50
(A's speed) : (B's speed) = √b : √a = √16 : √9 = 4 : 3.
Let us draw a figure below as per given question.
Let two ships started from point O at the speed of 30 km/hr and 20 km/hr respectively, after two hours they reach at points A and B.
Now, ?NOA = 32° and ?SOB = 58° ,
Then, ?AOB = 180° - (32° + 58°) = 90°
Since ?AOB is a right triangle in which OA = 2 x 30 = 60 km and OB = 2 x 20 = 40 km
Since, AB = ?OA2 + OB2
= ?(60)2 + (40)2
= ?5200
= 20?13
Let the number of pages be p.
Number of pages read on first day = 3p/8
Remaining pages = p - 3p/8 = (8p - 3p)/8 = 5p/8
Number of pages read on second day = 4/5 x 5p/8 = p/2
Now , remaining pages = p - [ 3p/8 + p/2]
= p - [(3p + 4p)/8] = [p- 7p/ 8]
= [(8p - 7p)/ 8] = p/8
According to the question
p/8 = 40
? p = 40 x 8
? p = 320
Required average
= Old average - Sold average
= ( 250 ) - ( 10 ) = 240
According to the formula .
Required time = (x + y) / (u + v)
Here, x = 70 m, y = 90 m, u = 10 m/s and v = 6 m/s
? Required time = (70 + 90) / (10 + 6) = 160/16 = 10 s
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