In a 40 litre mixture of alcohol & water, the ratio of alcohol and water is 5 : 3. If 20% of this mixture is taken out and the same amount of water is added then what will be the ratio of alcohol and water in final mixture?

Correct Answer: 1:1

Explanation:

Quantity of alohol in the mixture = 40 x 5/8 = 25 lit

Quantity of water = 40 - 25 = 15 lit

According to question,

Required ratio = $\frac{20 - 40 x \frac{20}{100} x \frac{5}{8}}{15 - 40 x \frac{20}{100} x \frac{3}{8} + 40 x \frac{20}{100}} = \frac{20}{15 - 3 + 8} = 1 : 1$

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