A container contains 40 litres of milk.From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container.

Correct Answer: 30

Explanation:

pool : kerosene 

   3  :  2(initially) 

   2  :  3(after replacement)

 

  R e m a i n i n g Q u a n t i t y I n i t i a l Q u a n t i t y = 1 - R e p l a c e d Q u a n t i t y T o t a l Q u a n t i t y

 

(for petrol)    2 3 = 1 - 10 k

 => K = 30

 Therefore the total quantity of the mixture in the container is 30 liters.

Correct Answer: 5

Explanation:

           Wine                         Water

            8L                              32L

            1                :               4

           20 %                           80% (original ratio)

           30 %                           70% (required ratio)

 

In  ths case, the percentage of water being reduced when the mixture is being replaced with wine.

 

so the ratio of left quantity to the initial quantity is 7:8

 

Therefore ,  7 8 = 1 - K 40

 

=> K = 5 Lit

Correct Answer: Rs. 18

Correct Answer: 63 Kg

Correct Answer: 10 liters

Explanation:

Number of liters of water in 125 liters of the mixture = 20% of 150 = 1/5 of 150 = 30 liters

 

Let us Assume that another 'P' liters of water are added to the mixture to make water 25% of the new mixture. So, the total amount of water becomes (30 + P) and the total volume of the mixture becomes (150 + P)

 

Thus, (30 + P) = 25% of (150 + P)

 

Solving, we get P = 10 liters

Correct Answer: 83.33 ml

Explanation:

Profit (%) = 9.09 % = 1/11

 

Since the ratio of water and milk is  1 : 11,

 

Therefore the ratio of water is to mixture = 1:12

 

Thus the quantity of water in mixture of 1 liter = 1000 x (1/12) = 83.33 ml

Correct Answer: 13 and 27

Correct Answer: 2:3

Correct Answer: 5:3

Correct Answer: 5 litres