8(6+5) - 10 = ?
? = 8(11) - 10
? = 88 - 10
? = 78.
'&' is a Logical Symbol and is called as Ampersand.
^ is called Caret
- is called Bar
v is called Reversed Caret.
About 15 - 20 blocks become a 1 mile. City blocks differ in sizes. They do not have a standard measurement. Every geographical area has its own average city block size.
A city block is a rectangular area in a city with several buildings with the streets around. It is also called "block" which, in a dictionary, is defined as an informal unit of distance from one intersection to the next.
As per the given series of letters, which can be classified as:-
Designs 1, 4, 8 ? Consist of three line segments
Designs 2, 5, 7 ? Consist of four line segments.
Designs 3, 6, 9 ? Consist of both straight lines and curved lines.
As we can see that ,
Figures 1, 4, 9 ? Garments
Figures 2, 5, 7 ? Study Materials/ Stationery
Figures 3, 6, 8 ? Geometrical Figures.
A regular Pentagon have 5 sides and 5 lines of symmetry.
This would not mean that K and L will always be together. It just implies that, if K is there, then L will also be there.
At the same time, it can happen that L is there but K isn't.
Remember, the condition is on K, not on L.
This question concerns a committee?s decision about which five of eight areas of expenditure to reduce. The question requires you to suppose that K and N are among the areas that are to be reduced, and then to determine which pair of areas could not also be among the five areas that are reduced.
The fourth condition given in the passage on which this question is based requires that exactly two of K, N, and J are reduced. Since the question asks us to suppose that both K and N are reduced, we know that J must not be reduced:
Reduced :: K, N
Not reduced :: J
The second condition requires that if L is reduced, neither N nor O is reduced. So L and N cannot both be reduced. Here, since N is reduced, we know that L cannot be. Thus, adding this to what we?ve determined so far, we know that J and L are a pair of areas that cannot both be reduced if both K and N are reduced:
Reduced :: K, N
Not reduced :: J, L
Answer choice (B) is therefore the correct answer.
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