Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R= =10% p.a
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
C.I=
=Rs.3972
Principal = Rs.16,000;
Time=9 months = 3 quarters;
Amount
=Rs.[16000x(1+5/100)³] =[16000x21/20x21/20x21/20]
= Rs.18522.
C.I
= Rs.(18522 - 16000)
= Rs.2522.
Interest for 1 year is the same whether it's simple interest or the compound interest.
Now interest of third year = 8575 - 7350 = 1225; means principal for this interest is 7350 if comound interest is takenIf 7350 is the principal interest = 1225
if 100 is the principal interest =(1225/7350) * 100 = 50/3 %
When a thing increases for two successive times the overall increase on initial amount = a + b + (a * b)/100
Therefore overall interest for two years = 50/3 + 50/3 + [(50/3)*(50/3)]/100 = 325/9 %
Therefore amount after 2 years = 100 + 325/9 = 1225/9
If 1225/9 is the amount principal =100
if 7350 is the amount principal =(900/1225)*7350 =5400
So sum = 5400; Rate = 50/3 %
Difference in C.I and S.I for 2 years
= Rs(696.30-660)
=Rs. 36.30.
S.I for one years = Rs330.
S.I on Rs.330 for 1 year =Rs. 36.30
Rate
= (100x36.30/330x1)%
= 11%
We know thatThe Difference between Compound Interest and Simple Interest for n years at R rate of interest is given by
Here n = 2 years, R = 20%, C.I - S.I = 56
The population grew from 3600 to 4800 in 3 years. That is a growth of 1200 on 3600 during three year span.
Therefore, the rate of growth for three years has been constant.
The rate of growth during the next three years will also be the same.
Therefore, the population will grow from 4800 by = 1600
Hence, the population three years from now will be 4800 + 1600 = 6400
Amount
= Rs[7500x(1+4/100)²]
=Rs.(7500 * 26/25 * 26/25)
=Rs.8112
C.I
= Rs(8112 - 7500)
=Rs.612
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