If 18 March 1994 falls on a Friday, then on which day of the week does 25 February 1995 fall in the Gregorian calendar?

Introduction / Context:
This is another relative date problem where you are given the weekday for 18 March 1994 and asked to find the weekday for 25 February 1995. The task requires counting the number of days between the two dates and understanding how leap years and ordinary years shift weekdays.

Given Data / Assumptions:
- 18 March 1994 was a Friday.
- We must find the weekday on 25 February 1995.
- Calendar: Gregorian.
- 1994 is not a leap year (not divisible by 4).
- 1995 is also a non leap year.

Concept / Approach:
We want to count the days from 18 March 1994 to 25 February 1995. After obtaining this number, we reduce it modulo 7 to find how many days forward the weekday shifts. Because both years are non leap years, we do not need to account for an extra day in February, but we must handle the month lengths carefully.

Step-by-Step Solution:
Step 1: Count days remaining in March 1994 from 19 March to 31 March: that is 13 days.Step 2: Add the days in the months from April 1994 through January 1995: April 30, May 31, June 30, July 31, August 31, September 30, October 31, November 30, December 31, January 1995 has 31 days.Step 3: Sum these: 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 31 = 306 days.Step 4: From 1 February 1995 to 25 February 1995 inclusive of the last date is 25 days, so from the day after 18 March 1994 up to 25 February 1995 we have 13 + 306 + 25 = 344 days.Step 5: Thus, from 18 March 1994 to 25 February 1995, the advance in days is 344 + 1 = 345 if counted inclusive, but in terms of weekday shift we only need the difference modulo 7, which for the span corresponds effectively to 344 days.Step 6: Compute 344 modulo 7. Since 7 * 49 = 343, the remainder is 1.Step 7: A remainder of 1 means that the weekday advances by one day from Friday.Step 8: One day after Friday is Saturday, so 25 February 1995 is a Saturday.

Verification / Alternative check:
You can also treat 1994 and 1995 as back to back non leap years, observing that from 18 March 1994 to 18 March 1995 you would cross 365 days and therefore advance the weekday by one day, arriving at Saturday. Then note that 25 February 1995 is a little earlier than 18 March 1995, and when you adjust the count correctly you still end up with a single day shift overall as captured in the detailed calculation above.

Why Other Options Are Wrong:
Wednesday, Monday, Sunday or Friday would correspond to larger or smaller shifts in the weekday when moving from Friday on 18 March 1994. For example, Friday again would mean a shift of zero days, which contradicts the non leap full year contribution plus the extra days in February. Only one forward shift to Saturday matches the correct modulo 7 result.

Common Pitfalls:
Common mistakes include miscounting the days in each month, especially when crossing from one year to the next, or forgetting that both 1994 and 1995 are non leap years. Others may mix up inclusive and exclusive counting when summing days. A careful month by month breakdown, followed by a modulo 7 reduction, helps avoid such errors.

Final Answer:
Given that 18 March 1994 was a Friday, 25 February 1995 was a Saturday.