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- Question
What is the difference between the banker's discount and the true discount on Rs.8100 for 3 months at 5%
Options- A. Rs. 2
- B. Rs. 1.25
- C. Rs. 2.25
- D. Rs. 0.5
- Correct Answer
- Rs. 1.25
ExplanationF = Rs. 8100
R = 5%T = 3 months = 1/4 years
Therefore BD - TD = 101.25-100 = Rs.1.25
- 1. The banker's discount on a bill due 6 months hence at 6% is Rs. 18.54. What is the true discount?
Options- A. Rs. 24
- B. Rs. 12
- C. Rs. 36
- D. Rs. 18 Discuss
- 2. If the true discount on a certain sum due 6 months hence at 15% is Rs 120.What is the bankers discount on the same for same time and the same rate.
Options- A. Rs.109
- B. Rs.119
- C. Rs.129
- D. Rs.139 Discuss
- 3. The present worth of a bill due sometime hence is Rs. 1100 and the true discount on the bill is Rs. 110. Find the banker's discount and the banker's gain.
Options- A. Rs.145
- B. Rs.136
- C. Rs.121
- D. Rs.112 Discuss
- 4. If the discount on Rs. 498 at 5% simple interest is Rs.18, when is the sum due?
Options- A. 8 months
- B. 11 months
- C. 10 months
- D. 9 months Discuss
- 5. The bankers discount and true discount on a sum of money due 8 months hence are Rs.120 & Rs.110 resp. Find the sum.
Options- A. 1457
- B. 1320
- C. 1140
- D. 1260 Discuss
- 6. The banker's discount of a certain sum of money is Rs. 72 and the true discount on the same sum for the same time is Rs. 60. The sum due is:
Options- A. 290
- B. 480
- C. 360
- D. 420 Discuss
- 7. The certain worth of a certain sum due sometime hence is Rs. 1600 and the true discount is Rs. 160. The banker's gain is:
Options- A. 15
- B. 16
- C. 14
- D. 13 Discuss
- 8. Two consecutive discounts x% and y% is equivalent to the discount
Options- A. (x-y+xy100)%
- B. (x+y+xy100)%
- C. (x-y-xy100)%
- D. (x+y-xy100)% Discuss
- 9. A boat sails 15 km of a river towards upstream in 5 hours. How long will it take to cover the same distance downstream, if the speed of current is one-fourth the speed of the boat in still water:
Options- A. 1.8h
- B. 3h
- C. 4h
- D. 5h Discuss
- 10. A man can row 9 km/h in still water. It takes him twice as long as to row down. Find the rate of stream of the river?
Options- A. 3 1⁄3 Kmph
- B. 3 1⁄9Kmph
- C. 4 2⁄3 Kmph
- D. 4 1⁄3 Kmph Discuss
Banker's Discount problems
Search Results
Correct Answer: Rs. 18
Explanation:
T= 6 months = 1/2 year
R = 6%
Correct Answer: Rs.129
Explanation:
B.G = S.I On T.D
= Rs. (120 * 15 * 1/2 * 1/100)
= Rs.9
B.D - T.D = Rs.9
B.D = Rs.(120 +9) = Rs.129
Correct Answer: Rs.121
Explanation:
T.D. =Ö(P.W.*B.G)
B.G. =(T.D.)2/ P.W.
= Rs.[(110x110)/ 1100]
= Rs. 11.
B.D.= (T.D. + B.G.) = Rs. (110 + 11) = Rs. 121.
Correct Answer: 9 months
Explanation:
F = Rs. 498
TD = Rs. 18
PW = F - TD = 498 - 18 = Rs. 480
R = 5%
=> T = 3/4 years = 9 months
Correct Answer: 1320
Explanation:
Sum = (B.D * T.D) / (B.D) -(T.D)
= (120 * 110) / (120 -110)
= 1320
Correct Answer: 360
Explanation:
Sum =(B.D. x T.D.)/(B.D. - T.D.)
= Rs. (72 x 60) / (72 - 60)
= Rs. (72 x 60) /12
= Rs. 360.
Correct Answer: 16
Explanation:
B.G. =(T.D.)^2/P.W.
= Rs. (160*160)/1600 = Rs. 16.
Correct Answer: (x+y-xy100)%
Correct Answer: 3h
Explanation:
Upstream speed = B-S
Downstream speed = B+s
B-S = 15/5 = 3 km/h
Again B= 4S
Therefore B-S = 3= 3S
=> S = 1 and B= 4 km/h
Therefore B+S = 5km/h
Therefore, Time during downstream = 15/5 = 3h
Correct Answer: 4 2⁄3 Kmph
Explanation:
Let man’s rate upstream be x km/hr. Then his rate downstream is 3 x km/hr Given: Speed in still water = 9 (1/3) = 28/3 km/hr i.e, ½ (a+b) = 28/3 km/hr ½ (x+3x) = 28/3 2x = 28/3 x = 28/ 2 x 3 = 14/3 km/hr rate upstream b = 14/3 km/hr and rate downstream a = 14/3 x 3 = 14 km/hr speed of the current = ½ (a-b) = ½ (14 – 14/3) = ½ (42-14/3) = 28/6 = 4 (2/3) km/hr
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