We follow the given pattern :-
In Layer-I, the nine central cubes have only one face painted, four cubes at the corner have three faces painted and the remaining 12 cubes have two faces painted.
In each of the Layer-II, III and IV, the nine central cubes have no face painted, the four cubes at the corner have two faces painted and the remaining 12 cubes have one face painted.
In Layer-V, the nine central cubes have only one face painted, the four cubes at the corner have three faces painted and the remaining 12 cubes have two faces painted.
Thus, the number of cubes having three faces painted = 4 + 4 = 8
As we can see that ,
Four central cubes in Layer 2 and four central cubes in Layer 3 have no face painted. Thus, there are 8 such cubes.
As per the given all information in above question , we can say that
Cubes A to G = 7 and 1 backside cube will have 3 colours .
Alternatively, The four cubes at the corners of Layer 1 and the four cubes at corners of Layer 4 have three colours.
On the basis of given all above information , we can say that
There are four cubes in Layer?I and four cubes in Layer IV which have only one face painted red and all other faces not painted at all.
Thus there are eight such cubes.
As per the given all information in above question , we can say that
The central cube of middle row will be without paint.
We follow the given pattern :-
From first, second and third figure Orange, Red, Silver and White cannot be on the opposite face of Green colour.
Therefore, Violet is opposite to Green.
On the basis of following pattern in given dices , we can say that
No Cube is there with two red faces only.
All the eight cubes have three red faces.
On the basis of following pattern in given dices , we can say that
From the two views of blocks it is clear that when 10 is at the bottom, number 12 will be at the top.
On the basis of following pattern in given dices , we can say that
From the two views of the same dice it is clear that, B, C and E are on the faces adjacent to A.
So, D lies opposite to A.
On the basis of the given open dice in above question , we can say that
The dot will lie opposite one of the shaded surfaces.
Therefore, option (2) cannot be formed.
As per the given open dice in above question , we can see that
When paper is folded in the form of a cube, then
? lies opposite ?
+ lies opposite ÷
? lies opposite ?
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