We follow the given pattern :-
From first, second and third figure Orange, Red, Silver and White cannot be on the opposite face of Green colour.
Therefore, Violet is opposite to Green.
As per the given above open dice , we can see that
Stem will be opposite of Leaf.
Bud will be opposite of Flower.
Fruit will be opposite of Seed.
On the basis of following pattern in given open dice , we can say that
Five will be opposite to Four.
One will be opposite to Three.
Two will be opposite to Six.
According to question figure , we can say that
Five block are visible and Two block are invisible.
Hence , Total Number of blocks = 1 + 4 + 2 = 7
We follow the given pattern :-
From the two views of the dice it is clear that dice has been inverted as three dots are on the same side.
Therefore, when two is at the bottom, four will be on the top.
We follow the given pattern :-
The six symbols on the six faces of the given cube are: ?, ?, +, ?, × and ÷. From figure 1,2 and 4, ÷, ×, ? and + can not be opposite to circle.
Hence, from the four positions of the cube it is clear that the circle lies opposite triangle.
As per the given all information in above question , we can say that
The central cube of middle row will be without paint.
On the basis of given all above information , we can say that
There are four cubes in Layer?I and four cubes in Layer IV which have only one face painted red and all other faces not painted at all.
Thus there are eight such cubes.
As per the given all information in above question , we can say that
Cubes A to G = 7 and 1 backside cube will have 3 colours .
Alternatively, The four cubes at the corners of Layer 1 and the four cubes at corners of Layer 4 have three colours.
As we can see that ,
Four central cubes in Layer 2 and four central cubes in Layer 3 have no face painted. Thus, there are 8 such cubes.
We follow the given pattern :-
In Layer-I, the nine central cubes have only one face painted, four cubes at the corner have three faces painted and the remaining 12 cubes have two faces painted.
In each of the Layer-II, III and IV, the nine central cubes have no face painted, the four cubes at the corner have two faces painted and the remaining 12 cubes have one face painted.
In Layer-V, the nine central cubes have only one face painted, the four cubes at the corner have three faces painted and the remaining 12 cubes have two faces painted.
Thus, the number of cubes having three faces painted = 4 + 4 = 8
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