We follow the given pattern :-
One, two, five and six dot(s) are on the faces adjacent to the face having three dots.
Therefore, there should be four dots on the face opposite to face having three dots.
Two, three, four or five dots cannot be on the face opposite to face having six dots. Therefore, one dot lies opposite the face having six dots.
This question concerns a committee?s decision about which five of eight areas of expenditure to reduce. The question requires you to suppose that K and N are among the areas that are to be reduced, and then to determine which pair of areas could not also be among the five areas that are reduced.
The fourth condition given in the passage on which this question is based requires that exactly two of K, N, and J are reduced. Since the question asks us to suppose that both K and N are reduced, we know that J must not be reduced:
Reduced :: K, N
Not reduced :: J
The second condition requires that if L is reduced, neither N nor O is reduced. So L and N cannot both be reduced. Here, since N is reduced, we know that L cannot be. Thus, adding this to what we?ve determined so far, we know that J and L are a pair of areas that cannot both be reduced if both K and N are reduced:
Reduced :: K, N
Not reduced :: J, L
Answer choice (B) is therefore the correct answer.
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Answer A
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