The number of projections doubles in each step.
Every time the inner figure enlarges and become the outer figure and the row inner figure changes to new element.
In one step, the arrow and the small line segment turn to other side of the more line and in the next figure.
The circle at the corner of the square moves clock wise, where as the cross inside the square moves anti clock wise.
Addition of line increases to the element.
Consider the 1st step, initial number of cubes N3 after removal of 1st set of coloured cubes number of cubes left out is (N - 1)3 hence number of cubes removed in 1st step (i.e with colour 1) is
N3 - (N - 1)3 = 3N2 - 3N + 1
Similarly number of cubes removed in 2nd step (i.e with colour 2) is
Similarly number of cubes removed in 3rd step is (i.e with colour 3) and so on.
= 3(N - 1)2 - 3(N - 1) + 1
Number of cubes remaining after 1st step is (N - 1)3
Number of cubes remaining after 2nd step is (N - 2)3 and so on.
After step 1 number of cubes with exactly 2 face painted is 4(N - 1) + (N - 2) = 5N - 6
Similarly after 2nd step number of cubes with exactly 2 face painted is 5(N - 2) - 6 = 5N - 11
And after 3rd step number of cubes with exactly 2 face painted is 5(N - 2) - 6 = 5N - 16
So total number of such cubes is 15N - 33 out of the given options only option B satisfy the given condition.
The tail of the figured moves 45 degree clock wise.
Similar figure appears in every second figure box. For the first figure, upper figure and lower figures interchanged in their place and similarly for the second box figure the left hand side and right hand side do the same.
Answer C
First Arrow inverts, on the 3rd figure the triangle and the diagonally opposite figure inverts again the arrow inverted, then the other figure inverts on the same way.
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