According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
So A is the heaviest in the weight.
According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
Descending order of weights of the articles will be
A, B, E, D, C
According to the question,
Sunita is taller than Seema and Renu.
1. Sunita > Seema/Renu.
Renu is shorter than Radha and Gauri
2. Renu < Radha/Gauri.
Bina is taller than Radha.
3. Bina > Radha.
Bina shorter than Sunita.
4. Bina < Sunita.
Sunita is not the tallest and Renu is not the shortest.
5. Sunita (not tallest)
6. Renu (not Shortest)
On arranging the above data, we get
from 3 and 4,
7. Sunita > Bina > Radha
from 7 and 1,
8. Sunita > Bina > Radha > Renu/Seema.
from 8 , 5 and 6.
? Gauri > Sunita > Bina > Radha > Renu > Seema.
Gauri is tallest among them.
According to the question,
Sunita is taller than Seema and Renu.
1. Sunita > Seema/Renu.
Renu is shorter than Radha and Gauri
2. Renu < Radha/Gauri.
Bina is taller than Radha.
3. Bina > Radha.
Bina shorter than Sunita.
4. Bina < Sunita.
Sunita is not the tallest and Renu is not the shortest.
5. Sunita (not tallest)
6. Renu (not Shortest)
On arranging the above data, we get
from 3 and 4,
7. Sunita > Bina > Radha
from 7 and 1,
8. Sunita > Bina > Radha > Renu/Seema.
from 8 , 5 and 6.
? Gauri > Sunita > Bina > Radha > Renu > Seema.
Seema is shortest.
According to the question,
Sunita is taller than Seema and Renu.
1. Sunita > Seema/Renu.
Renu is shorter than Radha and Gauri
2. Renu < Radha/Gauri.
Bina is taller than Radha.
3. Bina > Radha.
Bina shorter than Sunita.
4. Bina < Sunita.
Sunita is not the tallest and Renu is not the shortest.
5. Sunita (not tallest)
6. Renu (not Shortest)
On arranging the above data, we get
from 3 and 4,
7. Sunita > Bina > Radha
from 7 and 1,
8. Sunita > Bina > Radha > Renu/Seema.
from 8 , 5 and 6.
? Gauri > Sunita > Bina > Radha > Renu > Seema.
Third
According to the question,
Sunita is taller than Seema and Renu.
1. Sunita > Seema/Renu.
Renu is shorter than Radha and Gauri
2. Renu < Radha/Gauri.
Bina is taller than Radha.
3. Bina > Radha.
Bina shorter than Sunita.
4. Bina < Sunita.
Sunita is not the tallest and Renu is not the shortest.
5. Sunita (not tallest)
6. Renu (not Shortest)
On arranging the above data, we get
from 3 and 4,
7. Sunita > Bina > Radha
from 7 and 1,
8. Sunita > Bina > Radha > Renu/Seema.
from 8 , 5 and 6.
? Gauri > Sunita > Bina > Radha > Renu > Seema.
Bina occupies the third position from the top
According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
E is heavier than D and C.
According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
So, E is lighter in weight than A and B.
According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
So lightest in weight is C.
Arrangement in descending order,
Krishna > Guru > Raghu > Raja
Hence, Krishna is the fastest from all of them.
If the 5th day of the month is Tuesday. Then, first day of the month will be Friday. The third Friday will fall on 15th of the month. So, the date 3 days after 3rd Friday will be 19th.
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