If the positions of the first and the fifth digits of the number 83721569 are interchanged, similarly, the positions of the second and the sixth digits are interchanged, and so on, which of the following will be the third from the right end after the rearrangement?

According to the question,
Rajnish is older than Rajesh and Raman.
Rajnish > Rajesh, Raman..........(i)
Ramesh is older than Rajesh but younger than Rajeev.
Rajeev > Ramesh > Rajesh........(ii)
Raman is older than Rajeev.
Raman >Rajeev.......................(iii)
Combining all, we get
Rajinish > Raman > Rajeev > Ramesh > Rajesh

According to question,
Fifteen children are standing in a row facing north.
Left Side Position 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th Right Side position
Ravi is is eighth from the left end.
Left Side Position 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th Right Side position
......................................................................................Ravi
Ravi is to the immediate left of Prabha.
Left Side Position 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, ........10th, 11th, 12th, 13th, 14th, 15th Right Side position
......................................................................................Ravi, Prabha
Arjun is second from the right end.
Left Side Position 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, ........10th, 11th, 12th, 13th, 14th, 15th Right Side position
......................................................................................Ravi, Prabha........................................Arjun

8th, 9th, 14th
Ravi Prabha Arjun

Let us assume the number of boys in school be B.
Then number of girls in school = 2B
According to question,
B + 2B = 180
3B = 180
B = 180/3 = 60
Number of boys = 60
Number of girls = 120
Rupesh (a boy) ranked 34^th from top and 18 girls are ahead of Rupesh.
Number of boys after the rank of Rupesh = 60 ? 16 = 44

The specified digits are 8, 2 and 9. Now, we know a perfect square number does not have 8 and 2 at unit's place. Therefore, we can make only two three-digit numbers from it, i.e., 829 and 289. Among these two numbers, 289 is a perfect square number, i.e., square of 17. Thus, unit's digit is 7 and ten's digit is 1.

Four times 3 present together with 2 and 7, where 2 and 7 present either side of 3.
1 1 1 1 3 3 2 2 [2 3 7] 7 3 3 3 6 6 4 [7 3 2] 4 9 8 7 [7 3 2] 3 3 3 4 4 [2 3 7]

According to question,
In a row of boys Akash is fifth from the left
Left 1 - 2 - 3 - 4 - Akash - 6 - 7 - 8 - 9 - 10 - 11 - 12 .................................................................................................................. Right
If Akash is twenty-fifth from the right then
Left 1 - 2 - 3 - 4 - Akash - 6 - 7 - 8 - 9 - 10 - 11 - 12 - 13 -14 - 15 -16 -17 -18 -19 - 20- 21- 22 - 23- 24- 25 -26 -27 -28 - 29 Right
Nikhil is eleventh from the right.
Left 1 - 2-3 -4 - Akash - 6 -7- 8- 9-10 -11-12- 13-14- 15 -16-17-18 - Nikhil -20-21-22 - 23 - 24 - 25-26 -27- 28- 29 Right

There are (25 ? 11? 1) = 13 boys between Akash and Nikhil.

According to given question,
If the positions of the first and the sixth digits of the group of digits 3 5 9 7 2 8 0 1 6 4 are interchanged.
New number after interchange = 8 5 9 7 2 3 0 1 6 4
Then the positions of the second and the seventh digits are interchanged.
New number after interchange = 8 0 9 7 2 3 5 1 6 4

After interchanging the number becomes as follows: 8 0 9 7 2 3 5 1 6 4

fourth digit from the right end after the rearrangement : 5

Total students = [ First position of Ganesh + Second position of Rajan ] ?1
Total students = [12 + 20] ? 1 = 31

Number of persons between Vijay and Jack = 48 ? (14 + 17) = 17
Now, Mary lies in middle of these 17 persons i.e, at the eighth position.
So, number of persons between Vijay and Mary = 7.

After exchanging positions, Bhusan becomes fifteenth instead of seventh from the left, it means there are 7 students between them. So Motilal's position from the right will become twelfth. [i.e., (15 ? 7) + 4 = 12]