From the given condition ,
cost incurred in path 2 is equal to that in path 3 then T3 = 0
Similarly ,equating cost of path 3 and path 4 T7 = 0
Equating cost of path 4 and path 5 we will get
260 + T6 + T8 = 230 + T5
? T5 = T6 + T8 + 30
Equating cost of path 1 and path 2 we will get ,
240 +T1 = 260 + T2+ T4
or T1 = T2 + T4 + 20
For minimum total cost T1 = 20 and T5 = 30 then cost incurred is Rs 260.
Therefore , the minimum cost of travel from X to Y is Rs 260 .
the pattern is ... babc
All are rodents or rat family, except cat.
Barrow' is man-driven cart whereas others are usual.
Except option (d), all letters in pairs having difference of four.
The relationship is x : (x2 - 9).
63/3 = 21
27/3 = 9
F
Except option (c) rest all are perfect squares.
Except, `Plate', all two in number.
All other terms are used to denote the size.
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