Discussion
Home ‣ Verbal Reasoning ‣ Routes and Networks Comments
- Question
- If the government wants to ensure that all routes from S to T get the same amount of traffic, then a feasible set of toll charged (in rupees) at junctions A, B, C and D respectively to achieve this goal is :
Options- A. 0, 5, 2, 2
- B. 0, 5, 4, 1
- C. 1, 5, 3, 3
- D. 1, 5, 3, 2
- Correct Answer
- 1, 5, 3, 2
ExplanationAs per the given diagram , we can see that
Let the toll charged at junctions A, B, C and D be a, b, c and d respectively.
Then 1st we will list down all the routes and corresponding cost of travel.
Here in this case all 5 routes have the same toll charge hence 14 + a = 7 + b + c = 13 + d = 9 + a + b = 10 + c + d
After solving we will get a = 1, b = 5, c = 3 and d = 2 - 1. If the government wants to ensure that all motorists travelling from S to T pay the same amount ( fuel costs and toll combined ) regardless of the route they choose and the street from B to C is under repairs ( and hence unusable ), then a feasible set of toll charged (in rupees) at junctions A, B, C and D respectively to achieve this goal is :
Options- A. 2, 5, 3, 2
- B. 0, 5, 3, 1
- C. 1, 5, 3, 2
- D. 2, 3, 5, 1 Discuss
- 2. In the adjoining figure, the lines represent one-way roads allowing travel only northwards or only westwards. Along how many distinct routes can a car reach point B from point A?
Options- A. 15
- B. 56
- C. 120
- D. 336 Discuss
- 3. Eight cities A, B, C, D, E, F, G and H are connected with one-way roads R 1, R 2, R 3, R 4, R 5 and R 6 in the following manner:
R1 leads from A to C via B;
R2 leads from C to D and then via B to F;
R3 leads from D to A and then via E to H;
R4 leads from F to B via G;
R5 leads from G to D; and R6 leads from F to H.
The minimum number of road segments that have to be blocked in order to make all traffic form B to D impossible is
Options- A. 5
- B. 4
- C. 3
- D. 2 Discuss
- 4. What is the maximum quantity of natural gas than can be transported from M to R?
Options- A. 11 units
- B. 7 units
- C. 9 units
- D. 6 units Discuss
- 5. For which 2 cities it can be safely concluded that they have natural gas plants?
Options- A. M and P
- B. M and O
- C. P and N
- D. M and N Discuss
- 6. The government wants to devise a toll policy such that the total cost to the commuters per trip is minimized. The policy should also ensure that not more than 70 percent of the total traffic passes through junction B. The cost incurred by the commuter travelling from point S to point T under this policy will be:
Options- A. $ 7
- B. $ 9
- C. $ 10
- D. $ 13 Discuss
- 7. If the government wants to ensure that the traffic at S gets evenly distributed along streets from S to A, from S to B, and from S to D, then a feasible set of toll charged (in rupees) at junctions A, B, C, and D respectively to achieve this goal is:
Options- A. 0, 5, 4, 1
- B. 0, 5, 2, 2
- C. 1, 5, 3, 3
- D. 1, 5, 3, 2 Discuss
- 8. If the government wants to ensure that no traffic flows on the street from D to T, while equal amount of traffic flows through junctions A and C, then a feasible set of toll charged (in rupees) at junctions A, B, C and D respectively to achieve this goal is
Options- A. 1, 5, 3, 3
- B. 1, 4, 4, 3
- C. 1, 5, 4, 2
- D. 0, 5, 2, 3 Discuss
- 9. Find the ratio of maximum to minimum distance between A and H if condition is that traveling a city more than once is not allowed.
Options- A. 37 : 14
- B. 37 : 23
- C. 39 : 14
- D. None of these Discuss
- 10. Find the total number of paths from city H to city A if condition is that traveling a city more than once is not allowed.
Options- A. 44
- B. 55
- C. 59
- D. None of these Discuss
Routes and Networks problems
Search Results
Correct Answer:
Explanation:
As per the given figure , we can see that
Let the toll charged at junctions A, B, C and D be a, b, c and d respectively.
Then 1st we will list down all the routes and corresponding cost of travel.
Since Route BC is under repair hence route S-B-C-T is not in use.
Rest all four have the same toll charges hence 14 + a = 9 + a + b ? b = 14 - 9 = 5
Similarly 10 + c + d = 13 + d ? c = 13 - 10 = 3
Hence Options 4 is ruled out, now if we check option rest 3 options we will find out that option 2 and 3 both are correct. Option (2)/(3) Inconsistent options .
Correct Answer: 56
Explanation:
Here , number of vertical steps ( v ) = 3
Number of horizontal steps ( h ) = 5
Then in this case total number of ways is given by h+vCh = h+vCv = 8C3 = 6 x 7 x ( 8/6 ) = 7 x 8 = 56.
Hence , 56 distinct routes can a car reach point B from point A .
Correct Answer: 2
Explanation:
On the basis of above given question , we can say that
We can block B to D if A to B means R1 and B to F means R2 is blocked.
Therefore minimum 2 ways needed to be block.
Correct Answer: 6 units
Explanation:
From the above given figure and the conditions R can receive only 6 units (5 + 1) of natural gas if utilization is 100%.
Therefore , required answer will be 6 units.
Correct Answer: M and P
Explanation:
We know that cities M and P are gas plants.Hence , option A will be correct answer .
Correct Answer: $ 10
Explanation:
On the basis of above given question , we can say that
There must be one other route other than those involving B.
We must take S - D - C - T as the other route.
S - B - C - T, if toll at B = 3, total cost = 10
S - D - C - T, if toll at D and C is 0, total cost is 10.
Hence ,$ 10 is the least cost.
Correct Answer: 0, 5, 4, 1
Explanation:
According to question ,
If all the five routes have the same cost, then there will be an equal flow in all the five routes, i.e. 20% in each route.
But then the percentage of traffic in S - A = 20% (Only one route involving S - A)
S - B = 40% (As there are two routes involving S - B)
S - D = 40% (As there are two routes involving S - D)
But here the given condition that traffic in S-A is equal to that in S - B, which in turn is equal to S - D is not satisfied.
Of the routes, that can be used the number of routes involving S - A must be the same as S - B, which in turn is same as that as S - D.
That is possible only when we block the junction C and that can be done by taking higher toll charge at C to achieve this goal c > 3.
Hence , required answer will be option A .
Correct Answer:
Explanation:
From the given diagram ,
Let the toll charged at junctions A, B, C and D be a, b, c and d respectively.
Then 1st we will list down all the routes and corresponding cost of travel.
Since the cost of travel including toll on routes S-A-T, S-B-C-T, S-B-A-T and S-D-C-T is the same. And D-T has no traffic due to high toll charge at D.
From the last solutions we will get b = 5, 14 + a = 7 + b + c = 12 + c, or a + 2 = c 7 + b + c = 10 + c + d = 12 + c or d = 2, hence the result is B = 5, d = 2 and c-a = 2 that is satisfied by option (E).
Correct Answer: 37 : 14
Explanation:
From the above given diagram , we can see that
Maximum distance is when path taken is-
A ? D ? C ? B ? G ? E ? F ? H = 1300 + 500 + 200 + 400 + 400 + 300 + 600 = 3700 km
Minimum distance is when path taken is-
A ? C ? G ? H = 600 + 400 + 400 = 1400 km
Hence , Required ratio is 37 : 14.
Correct Answer: 55
Explanation:
Number of paths is as follows:
Starting from HGB: HGBA, HGBCA, HGBCDA, HGBCEDA, HGBCEFDA (Total 5 paths)
Starting from HGC: HGCA, HGCBA, HGCDA, HGCEDA, HGCEFDA (Total 5 paths)
Starting from HGE: HGECA, HGECBA, HGECDA, HGEDCA, HGEDCBA, HGEDA, HGEFDCBA, HGEFDCA, HGEFDA (Total 9 paths)
Starting from HEG: HEGBA, HEGCBA, HEGCA, HEGCDA (Total 4 paths)
Starting from HEC: HECGBA, HECBA, HECA, HECDA (Total 4 paths) Starting from HED: HEDCBGA, HEDCBA, HEDCA, HEDA (Total 4 paths)
Starting from HEF: HEFDCGBA, HEFDCBA, HEFDCBA, HEFDCA, HEFDA (Total 5 paths)
Starting from HFE: HFEGBA, HFECGBA, HFECBA, HFECA, HFEDCGBA, HFEDCBA, HFEDCA, HFEDA, (Total 8 paths)
Starting from HFD: HFDEGBA, HFDEGCA, HFDEGBCA, HFDECGBA, HFDECBA, HFDECA, HFDCEBGA, HFDCGBA, HFDCBA, HFDCA, HFDA (Total 11 paths)
Total number of paths is: 5 + 5 + 9 + 4 + 4 + 4 + 5 + 8 + 11 = 55
Hence , the total number of paths from city H to city A is 55 .
Comments
There are no comments.More in Verbal Reasoning:
Programming
Copyright ©CuriousTab. All rights reserved.